. Locomotive engineering : a practical journal of railway motive power and rolling stock . ofan !,\-in. hole being .3712), /=the pitch,and 7= the thickness of the sheet. Sub-stituting values, lii-?7if = .6q. The for this is the number of rows of rivetstimes the area of the rivet hole, divided bythe pitch times the thickness of the ma-terial in the shell. Example: ()-f-()=.69. I would state that this formula and rule forthe rivets give a higher shearing strengthto the rivets than advisable for iron rivetsin a steel sheet, it being 53,252 lbs. persquare inch, where 45,000 l
. Locomotive engineering : a practical journal of railway motive power and rolling stock . ofan !,\-in. hole being .3712), /=the pitch,and 7= the thickness of the sheet. Sub-stituting values, lii-?7if = .6q. The for this is the number of rows of rivetstimes the area of the rivet hole, divided bythe pitch times the thickness of the ma-terial in the shell. Example: ()-f-()=.69. I would state that this formula and rule forthe rivets give a higher shearing strengthto the rivets than advisable for iron rivetsin a steel sheet, it being 53,252 lbs. persquare inch, where 45,000 lbs. per squareinch is plenty high. Table No. 2 will givethe shearing strength of iron rivets from^^-in. up to and including i j^-in., which, Ithink, will coverall that will be needed forsome time. Remember, these values willbe figured from the diameter of the rivethole, or the driven rivet js-in. larger thanthe rivet previous to driving. Thesevalues are secured by multiplying the areaof the hole by 45,000. For example, find ♦Foreman Boiler-maker, C. M. & St. P. Ry.,Dubuque, requires a |f,-in. rivet hole ; {^ = .8125, and3K = 3-5, -nd ys = .375- This joint wouldfail in one of two different ways—by frac-ture of the sheet through either one of theoutside rows of rivet holes, or by shearingoff the strength of the solid sheet 3^ in. long is X .375 X 55,000 = 72,187The strength of the sheet, minus thediameter of the rivet hole, ( - .8125) X .375 X 55,ooo = 55,429The shearing strength of three rivets,as there are four halves and onewhole rivet exposed to single shear,referring to Table No. 2, it requires23,332 lbs. to shear one }i-. rivet, 3 X 23,332 = 69,996The sheet through the rivet holes is ; consequently divide that strengthby the strength of the solid sheet for thepercentage of strength of the joint orseam: 55,429-7-72,187= 12 is a double-riveted seam of ^4^-iu. 363 one rivet, as two halves are ex-posed at--/and ^-7, (6.
Size: 1649px × 1514px
Photo credit: © Reading Room 2020 / Alamy / Afripics
License: Licensed
Model Released: No
Keywords: ., bookcentury1800, bookdecade1890, booksubjectrailroa, bookyear1892
