. Perspective for art students . Fio. 188.—The upper part of the house found. from I, and along it measure by 30°, the distancesacross the gable—that is, 10 feet for the full width, and5 feet for the middle. We thus get point M and N we now want a vertical height of 5 feet. Wemake a wall of height by bringing a line from 60through N to the , raise our 5 feet, and take a lineback to 60; where a line up from N cuts this lineis point 0, the apex of the gable. 248 t^erspeciive From I a line to 60 gives the side. It ismeasured from 60, Note particularly that the
. Perspective for art students . Fio. 188.—The upper part of the house found. from I, and along it measure by 30°, the distancesacross the gable—that is, 10 feet for the full width, and5 feet for the middle. We thus get point M and N we now want a vertical height of 5 feet. Wemake a wall of height by bringing a line from 60through N to the , raise our 5 feet, and take a lineback to 60; where a line up from N cuts this lineis point 0, the apex of the gable. 248 t^erspeciive From I a line to 60 gives the side. It ismeasured from 60, Note particularly that the line of height for gettingthe 5 feet up from N to 0 is not the same line of heightas was previously used for FGr and K. That line goesto ; this goes to 60. The junction between house and bank can be foundin two ways. The student will remember that in Fig. 187 the linefrom E to is under A. Consequently, if a line ,. AVP. Fig. 189.—The junction obtained by means of the ground-plane. be dropped from A it will find what we may call thefoundation of the house on the ground-plane at , the plane of the side of the house does not passthrough , which is the concerned in EA, butwe can make AY from 60, which is the con-cerned in the side of the house. YA will be where theplane of the house cuts the bank, and YA can thus becontinued up to the top at Z. We do not already possess point X, as we do A; weonly have M above it. But we can find M on the Solving Problems 249 ground by drawing from A a line under IM. IMvanishes at 30° left, so AM must vanish there too, not A line being thus drawn from A to 30, anda vertical dropped from M, we get M. Just as A isrelated to E and E to A, so M can be related to W andW to X by drawing through M a line from to theedge of the bank, and then another from W to ,giving method is to find the of the lines of Wf K
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