. Railway and locomotive engineering : a practical journal of railway motive power and rolling stock . he remainder of the flange is wear-ing straight. What is the cause of this?A.—There are several causes that couldproduce this effect. A bent axle is one of tile chief causes of the irregular wear-ing of flanges. This is generally ac-companied with heating in the drivingboxes, and if mi indications of heatingis manifested, it is safe to assume thatthere is a deflection in the rim of thewheel which may have been caused dur-ing the process of pressing in the crankpins. Wheels of large diameters
. Railway and locomotive engineering : a practical journal of railway motive power and rolling stock . he remainder of the flange is wear-ing straight. What is the cause of this?A.—There are several causes that couldproduce this effect. A bent axle is one of tile chief causes of the irregular wear-ing of flanges. This is generally ac-companied with heating in the drivingboxes, and if mi indications of heatingis manifested, it is safe to assume thatthere is a deflection in the rim of thewheel which may have been caused dur-ing the process of pressing in the crankpins. Wheels of large diameters aresometimes slightly bent and not infre-quently cracked by careless adjustmentof points of resistance while the axlesand crank pins are being pressed intoplace. COMPOUND INDEXING. (3) E. E., Mattoon, 111., writes:Please explain the art of figuringcompound indexing for a gear wheelwith 73 teeth. A.—In indexing on amachine for cutting teeth in a gearwheel the question simply is: How manydivisions of the machine index have tobe advanced to advance a unit of thenumber required? Suppose the number. INDEXING FOR GEAR WHEELS. of divisions in wheel of machineto be 180. Divide 180 by 73 (the num-ber of teeth required) =2?-5, the num-ber of turns required on worm , if we have a worm wheel with36s teeth the problem would be a sim-ple one, as 34__i70 73~365-Hence, 2 turns of the worm wheel and170 teeth of the 365 in the worm wheelindex would be the exact division fora wheel containing 73 teeth. But supposing the number of teethin the worm wheel index was 220. Then 22OX ?i=I02 — 73 73 This would necessitate 2 turns of theworm wheel and 102 teeth of the 220teeth in the worm wheel index for thefirst tooth of the 73 required, and 2 turnsand 103 teeth for the second tooth, andso on alternately until the completionof the 73 teeth. i his is the nearest approach to ac-curacy with a worm wheel of 220 teeth,and involves a fractional variation in thesize of the teeth amounting
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Keywords: ., bookcentury1900, bookdecade1900, booksubjectrailroa, bookyear1901
