. Fruit farming: practical and scientific, for commercial fruit growers and others. Fruit-culture. 181 Proceed as before. Divide 190,000 by the length of A B which we will suppose is 5 chains (500 links). 190,000 -=- 500 = S'SO chains (3 chains 80 links). Measure off along A D and B C a distance of chains and put in pegs as before in the field. The point to be borne in mind in this kind of work is that the area must be worked out on the plan before any pegging out of measurements in the field. Before closing this short article it may be worth while considering the measure- ment of an area
. Fruit farming: practical and scientific, for commercial fruit growers and others. Fruit-culture. 181 Proceed as before. Divide 190,000 by the length of A B which we will suppose is 5 chains (500 links). 190,000 -=- 500 = S'SO chains (3 chains 80 links). Measure off along A D and B C a distance of chains and put in pegs as before in the field. The point to be borne in mind in this kind of work is that the area must be worked out on the plan before any pegging out of measurements in the field. Before closing this short article it may be worth while considering the measure- ment of an area which it is impossible to see across on account of fruit trees or other obstruction to sight. Take as an example the orchard, Fig. 6 N N N N exact point in line by aid of the cross staff and put in a pole at this point. Now pro- ceed to chain from A to this intermediate point and then on to B and lay out the figure in triangles as before explained. Should this method fail nothing is left but to measure round the area as follows. Measure from A to D, and take the bear- ing of the line with a compass, then from D to B, B to C, C to A, taking the bearing in each case. (See Fig. 5.) Now draw on paper a line N S to indi- cate the direction of North. Draw A D to scale from a point midway in this line bearing the number of degrees ascertained for it by the compass (say 120 deg.). Draw parallel to N S i another line N S 2 and from the point D draw DB to scale bearing the number of degrees ascertained for it by the compass (say 80 deg.).. It is impossible to see from pole A to pole B on account of the trees. Try first, if it is possible to see both poles from an intermediate point between them in the middle of the orchard. It is of ten the case, when one cannot see from one point to the other, that both poles are visible from a middle point. If this is so then find the Proceed with the remaining lines as described, and the proof of correct read- ing of the angles lies in the fact that
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