Electronic apparatus for biological research electronicappara00dona Year: 1958 RESISTANCE AND CAPACITANCE IN SERIES any time t after opening the switch R dt. Jo Jo ^ The solution is Vji=^ Vq = IR{1 — e'^'^^) 1 But iji = I— ic Figure If the generator and switch are then disconnected, the capacitance discharges again, through the resistance, and Vji = Vq= y^-tiRC^ where V is the potential difference to which the capacitance was charged. If the original charging process was substantially completed, V is, of course, equal to IR. Resistance and capacitance in parallel, connected to consta

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Electronic apparatus for biological research electronicappara00dona Year: 1958 RESISTANCE AND CAPACITANCE IN SERIES any time t after opening the switch R dt. Jo Jo ^ The solution is Vji=^ Vq = IR{1 — e'^'^^) 1 But iji = I— ic Figure If the generator and switch are then disconnected, the capacitance discharges again, through the resistance, and Vji = Vq= y^-tiRC^ where V is the potential difference to which the capacitance was charged. If the original charging process was substantially completed, V is, of course, equal to IR. Resistance and capacitance in parallel, connected to constant-voltage alternator (Figure ) Figure In this case, we have: Current in the resistance = V R V _jV J'Xq Xq Current in capacitance = Therefore, total current = '^l 15 + y~ I V So the impedance = 1 (-; + Xc) R^ Xc Compare this with the expression for two resistances in parallel. If we take the expression for the impedance of the parallel combination and rewrite it in the form Z = -jXc. R R-jXc 41

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