The elements of Euclid for the use of schools and colleges : comprising the first two books and portions of the eleventh and twelfth books; with notes and exercises . et at K. Through K draw KL parallel to EA or FH; [I. 31. and produce HA, GB to the points Z, M. Then HLKF is a parallelogram, of which the diameteris HK\ and AG, ME are parallelograms about HK, andZ 5,-6i^ are the complements. Therefore LB is equal to BF. [I. 43. But BF is equal to the triangle C. [Oonstruction. Therefore LB is equal to the triangle G. [Axiom 1. BOOK 1. 44, 45. 47 ^nd because the angle GBEh equal to the angle A B
The elements of Euclid for the use of schools and colleges : comprising the first two books and portions of the eleventh and twelfth books; with notes and exercises . et at K. Through K draw KL parallel to EA or FH; [I. 31. and produce HA, GB to the points Z, M. Then HLKF is a parallelogram, of which the diameteris HK\ and AG, ME are parallelograms about HK, andZ 5,-6i^ are the complements. Therefore LB is equal to BF. [I. 43. But BF is equal to the triangle C. [Oonstruction. Therefore LB is equal to the triangle G. [Axiom 1. BOOK 1. 44, 45. 47 ^nd because the angle GBEh equal to the angle A BM, [ and Iike\\ise to the angle D; [Comtructioiu the angle ABM is equal to the angle D. [Axiom h Wherefore to the given straight line AB the parallelo-gram LB is applied, equal to the triangle C, and havingthe angle ABM equal to the angle D. PROPOSITION 45. PROBLEM. To describe a parallelogram equal to a given rectilinealfigure, and hazing an angU equal to a given rectilinealojngle. Let A BCD be the given rectilineal figure, and E thegiven rectilineal angle: it is required to describe a par-allelogram equal to A BCD, and having an angle equal to
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Keywords: ., bookcentury1800, booksubjectgeometry, booksubjectmathematicsgree
