. Hawkins electrical guide. Questions, answers & illustrations; a progressive course of study for engineers, electricians, students and those desiring to acquire a working knowledge of electricity and its applications; a practical treatise. n (3) must be substituted in equation(2), giving Ef=2ir/LI (4) writing simply I for the virtual pressure. Since the pressure impressed on a circuit is considered as made upof two components, one in phase with the current and one at right anglesto the current, the component E« or reactance drop as given inequation (4) may be represented by the line BC in fig
. Hawkins electrical guide. Questions, answers & illustrations; a progressive course of study for engineers, electricians, students and those desiring to acquire a working knowledge of electricity and its applications; a practical treatise. n (3) must be substituted in equation(2), giving Ef=2ir/LI (4) writing simply I for the virtual pressure. Since the pressure impressed on a circuit is considered as made upof two components, one in phase with the current and one at right anglesto the current, the component E« or reactance drop as given inequation (4) may be represented by the line BC in fig. , at rightangles to AB, and of a length BC, measured with the same scale as wasmeasured AB. to correspond to the value indicated by equation (4). 1,078 HA ELECTRICITY EXAMPLE.—In an alternating circuit, having an ohmic drop ofs volts, and a reactance drop of 15 volts, what is the impressed pressure? With a scale of say, H inch=one volt, lay off, in fig. 1,315, AB=5volts = 1 \i in., and, at right angles to it, BC -15 volts = ~ or 334 ins. JoinAC; this measures inches, which is equivalent to = , the impressed pressure. By using good paper, such as bristol board, a NON-INDUCTIVE COIL INDUCTIVE COIL. Pig. —Diagram of circuit containing 5 volts ohmic drop, and 15 volts reactance drop. A IS VOLTS B REACTANCE DROP SCALE: 1 IN.* 4 VOLTS / FlG. —Diagram for obtaining reactance drop in circuit containing 5 volts ohmic drop, volts impressed pressure. 6H pencil, engineers scale and triangles or square, such problems aresolved with precision. By calculation impressed pressure = V5I + 15* = volts. Note that the diagram is drawn with the side BC horizontalinstead of AB—simply to save space. ALTERNATING CURRENT DIAGRAMS 1,079 EXAMPLE.—In an alternating circuit, having an ohmic drop of 5volts and an impressed pressure of volts, what is the reactance drop? In fig. 1,317, draw a horizontal line of indefinite length and at
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