. Design of 40 K. W. inductor generator. the The extrene diameter of the field coil being 17 inches,the circia!iferential length is TTd = X .17 - inchesThen since the width of the ceil ie V inches, the afea of thec^aindrical radiating surface is 5yy,8 >: 7 = squ^ire inchesTo this must be added ^^bout 30 square inches of radiatingsurface on each side of the coil, as provided for in the con-struction of the bobbin; this naKes a total of 376 + 6 0 - 436 sqiiare inches .Hence ?89 / 436 = ,66 watts lost por snuare inch of radiat-ing surface. With airtperes flcuing thro

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. Design of 40 K. W. inductor generator. the The extrene diameter of the field coil being 17 inches,the circia!iferential length is TTd = X .17 - inchesThen since the width of the ceil ie V inches, the afea of thec^aindrical radiating surface is 5yy,8 >: 7 = squ^ire inchesTo this must be added ^^bout 30 square inches of radiatingsurface on each side of the coil, as provided for in the con-struction of the bobbin; this naKes a total of 376 + 6 0 - 436 sqiiare inches .Hence ?89 / 436 = ,66 watts lost por snuare inch of radiat-ing surface. With airtperes flcuing through the coil,the watts lost per square inch is approximalel3 1. The rise in temperature of the coil, in degrees Centi- 1 grade, as given b:- the folloiving formula, is enual to 52 X loss in v/atts / cyl, surface of bobbin in square incheor 52 X 289 / 376 = 40° with an excitation current of amperes. v;hen the currentis amperes, the rise in temperature is about 53°C. 1 Pisher-Hinnen, Continuous Current rynamcs, j^l899 ) 65.

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