Lessons in practical electricity; principles, experiments, and arithmetical problems, an elementary text-book . ed the positive electrodeor anode and the plate by which it leaves the solution is calledthe negative electrode or cathode. The constituent parts of theelectrolyte which are liberated at the surface of the electrodesare called ions; the ion liberated at the positive electrode beingcalled the anion, and that which appears at the negative elec-trode the cathion. Any vessel or apparatus used for perform-ing or measuring electrolysis is called a voltameter. In theelectrolysis of water hy
Lessons in practical electricity; principles, experiments, and arithmetical problems, an elementary text-book . ed the positive electrodeor anode and the plate by which it leaves the solution is calledthe negative electrode or cathode. The constituent parts of theelectrolyte which are liberated at the surface of the electrodesare called ions; the ion liberated at the positive electrode beingcalled the anion, and that which appears at the negative elec-trode the cathion. Any vessel or apparatus used for perform-ing or measuring electrolysis is called a voltameter. In theelectrolysis of water hydrogen is the cathion and oxygen theanion. 101. Electrolysis of Copper Sulphate.— Exp. 20: Fill the U tube, Fig. 94, with a solution of copper sul-phate, made by dissolving some copper sulphate crystals (bluestone)in water, and subject the solution to electrolysis, as in the case of thewater, using platinum electrodes. Metallic copper is deposited upon^ the negative electrode, that is the plate~^ becomes copper-plated. Oxygen gas isliberated at the positive platinum electrodeand sulphuric acid is \% The chemical symbol for copper sul- j} phate is CuS04 and by electrolysis it is r ~> ?$ separated into Cu (metallic copper) -^*tar and S04 (sulphion). The hydrogen Fig 95~^e°terr V°lta Sas liberated at the negative plate dis-places the Cu of the CuS04 formingH2S04 (sulphuric acid), and deposes the Cu on the negativeplate, while oxygen gas is liberated at the + platinum plate, ELECTROLYSIS. 81 as before. If the action is allowed to continue for some time,all the metallic copper is taken from the solution and will be noted by the solution changing from a deep to apale blue, as the change gradually takes place from coppersulphate to sulphuric acid. The action is represented asfollows : CuS04 = Cu -f S04 Sulphate of copper becomes copper and sulphion S04 + H20 = H2S04 + O Sulphion and water produce sulphuric acid and oxygen Exp. 21: Reverse the direction of
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