. Journal of electricity, power, and gas . ac is rotated until it passes through the intersection of 7%and 20%. The number 21 coincides with 20 and 7, therefore thepressure consumed over the line at full non-inductive load is21%. (When using Fig. 3b, numbers along ac, Fig. 4, are to bemultiplied by 2.) 21 represents full load on line, 10% will repre-sent half load, etc. The regulation at non-inductive full load isseen to be 9%. For full kiloivatt load at 085 power-factor movealong 21 to g; regulation equals 21^%. For full kilovolt-aml>crcload at 0-85 power-factor move along 21 to h : regula
. Journal of electricity, power, and gas . ac is rotated until it passes through the intersection of 7%and 20%. The number 21 coincides with 20 and 7, therefore thepressure consumed over the line at full non-inductive load is21%. (When using Fig. 3b, numbers along ac, Fig. 4, are to bemultiplied by 2.) 21 represents full load on line, 10% will repre-sent half load, etc. The regulation at non-inductive full load isseen to be 9%. For full kiloivatt load at 085 power-factor movealong 21 to g; regulation equals 21^%. For full kilovolt-aml>crcload at 0-85 power-factor move along 21 to h : regulation equals17%. For equal generator and receiver pressure at full load movealong 21 to arc marked 0%. The figure shows that for 09power-factor, for leading current, the receiver pressure would bepractically equal to the generator pressure for all loads; that is,the line would be Fi(r. iHulJ nize.) printed on tramrxu-ent celluloid. FiK. 6. DetorminiiiB Drop in iU is drawn with a as oa - EoJh - £o. oa = ah = h:.. on -fu- The device may be used to find the receiver pressure whenthe generator voltage is kept constant. In this problem the gen-erator pressure would be called 100%. Now, for a given currentdrawn by the receiver at a given power-factor the voltage over 122 JOURNAL OF ELECTRICITY, POWER AND GAS. [Vol. XXIV—No. 6 the transmission line represented by ag, Figs. 1 to 6, remains eon-stant; that is, the point g is a fixed point for the power-factorcos 6. If Et is 100%, to get the receiver pressure, E, we describea circular arc with g as center to cut oa in o, Fig. 6. The lengthoa is then E, and the length oo is the percentage drop inpressure over the line. But it is easily seen from Fig. 6 thatoo = fg, and therefore the percentage drop in pressure over theline when Ee is fixed at 100% is the horizontal distance from gto th
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