. Cyclopedia of textile work : a general reference library on cotton, woollen and worsted yarn manufacture, weaving, designing, chemistry and dyeing, finishing, knitting, and allied subjects . nds of twist, and what number of hanks of the loop yarn willweigh 1 pound ? Note—The length of 60s is double that of the unit length of + GO = 120 -^ 60 = 2 + 0 == GO -- 12 = 5 7 = G ^ 3 = 2 X 60 = 120 hanks. 12s = 6 ^ G = 1 X GO = 60 120 ^ GO = 2 pounds of -- 12 = 5 pounds of hanks of twist yarn weigh 7 pounds. GO -^ 7 = = 1 pound, using Itule 20 as


. Cyclopedia of textile work : a general reference library on cotton, woollen and worsted yarn manufacture, weaving, designing, chemistry and dyeing, finishing, knitting, and allied subjects . nds of twist, and what number of hanks of the loop yarn willweigh 1 pound ? Note—The length of 60s is double that of the unit length of + GO = 120 -^ 60 = 2 + 0 == GO -- 12 = 5 7 = G ^ 3 = 2 X 60 = 120 hanks. 12s = 6 ^ G = 1 X GO = 60 120 ^ GO = 2 pounds of -- 12 = 5 pounds of hanks of twist yarn weigh 7 pounds. GO -^ 7 = = 1 pound, using Itule 20 as in previous example. (a) 200 X 2 ^ ^ ^ -= 57L pounds of 60s. (b) 200 X 5 ^ ^ ^ = 142-1- pounds of 12s. Example. A loop yarn is composed of 2 threads of 8sworsted and 1 thread of 12s worsted; 21 inches of the former arerequired to 14 inches of the latter. What weight of each will berequired to produce 150 pounds of twist, and what number ofhanks per pound will the loop yarn contain ? 12 + (I of 12) = 18 -^ 8 = pounds. 12 + [l of 12) = 18 -^ 8 = 12 + 0 = 12 - 12 = 2i pounds. Twelve hanks of loop yarn weigh pounds. 12 ^- 2-j2j- hanks per pounds or loop counts. 266. en S z O a TEXTILE CALCULATIONS 21 and 150 X X = 61^\ of 3g = 61^4_ of 8s 150 X 1 ^ = 27^3_ of 12s 150 pounds of loop yarn. To Find the Weight of a Given Yarn to be Twisted Witha Yarn, the Weight and Counts Being Known. The problemmay now be put in a different way. There may be a givenquantity of one of the yarns, and it is required to find whatweight will be necessary to twist with it and just use it is obviously the reverse of the above proceeding, and at onceresolves itself into a simple proportion, being dependent only uponthe relative counts; thus 20s and 30s are to eacirother as 2 is to3, and, as the higher number is the lighter yarn, the proportionmust be inverse. Supposing then, that there are 400 pounds of 30s yarn andit is required to find how m


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