. Perspective for art students . Fig. 193.—^The various vanishingparallels. 3 is the same as between : where will its reflection vanish ? parallel of the reflection of AC will be 5. parallel must always proceed away from the eye forward. Putting down the angle equal to the angle between 2 and 3, it comes below 1, and so must be continued up through the eye into 5. This is shown in the solution Solving Problems 253 Fig. 195. We must also have a vanishing parallel forthe lines perpendicular to the mirror. These are 0, C,etc., and their vanishing parallel is 6. The top of the object is not le
. Perspective for art students . Fig. 193.—^The various vanishingparallels. 3 is the same as between : where will its reflection vanish ? parallel of the reflection of AC will be 5. parallel must always proceed away from the eye forward. Putting down the angle equal to the angle between 2 and 3, it comes below 1, and so must be continued up through the eye into 5. This is shown in the solution Solving Problems 253 Fig. 195. We must also have a vanishing parallel forthe lines perpendicular to the mirror. These are 0, C,etc., and their vanishing parallel is 6. The top of the object is not level, but slants downits slanting edges vanishing below in , shownin Fig. 194. The vertical line through is the Fis. 194.—The reflnction of an inclined line. of a vertical plane, containing AC, HF (see Fig. 195,the solution). In the object the top descends as itrecedes; that is, GTF is nearer than IH, and IH is thelower. In the image, however, IH is still the lower,but it is the nearer, and so the top ascends as it the of FH is below the of AC, the ofHF will be above the of CA. The of CA 254 Ferspectwe will be far out on the right. Our paper does not permit
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