. Electronic apparatus for biological research . 3-33ft G B,D Figure G,B,D. Figure of the answer; that the current in AB is one amp downwards. Since the currents divide inversely as the ratio of parallel resistances, the current CD must be | amp downwards. Thus the current in E-AC is l^amps downwards. In Figure , if we have 1| amps flowing from E to BD, the current down F-G must be 3 amps, and the total current suppUed to the network must be 4| amps. If we are told that the generator actually supplies 13 amps to the network, then the actual currents flowing in the various pa
. Electronic apparatus for biological research . 3-33ft G B,D Figure G,B,D. Figure of the answer; that the current in AB is one amp downwards. Since the currents divide inversely as the ratio of parallel resistances, the current CD must be | amp downwards. Thus the current in E-AC is l^amps downwards. In Figure , if we have 1| amps flowing from E to BD, the current down F-G must be 3 amps, and the total current suppUed to the network must be 4| amps. If we are told that the generator actually supplies 13 amps to the network, then the actual currents flowing in the various parts of the network are found merely by multiplying the assumed values by 13/4|. Finally the potential differences across the resistances are worked out by multiplying the current through each resistance by its value in ohms. 10
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