. Railway mechanical engineer . i-hi. plate, or in., allowing for one 11/16-in. ■Cross Bea rer.^t*. of Car* in. thick and 6JX ; a unit stress of The cover plate is actually made fswide, the net area being sq. in.,12,950 lb. per sq. in. Side Truss The load distribution for the body is shown in the follow-ing table and in Fig. 8. Tblss Loadingp, = 5 X 4 ft. 9/; in. X 452 = 10,840 Ps = m X Pi = Pi = J4 X Pi = p. = 5 ft. 2H in. X 4 ft. 9J4 in. X 452 +(}i + Pi) = 14,010 (Not on truss)Ps = 2 ft. %^i in. X 4 ft. 9!^ in. X 452 = 5,870 R = 5,420 Check 30,260
. Railway mechanical engineer . i-hi. plate, or in., allowing for one 11/16-in. ■Cross Bea rer.^t*. of Car* in. thick and 6JX ; a unit stress of The cover plate is actually made fswide, the net area being sq. in.,12,950 lb. per sq. in. Side Truss The load distribution for the body is shown in the follow-ing table and in Fig. 8. Tblss Loadingp, = 5 X 4 ft. 9/; in. X 452 = 10,840 Ps = m X Pi = Pi = J4 X Pi = p. = 5 ft. 2H in. X 4 ft. 9J4 in. X 452 +(}i + Pi) = 14,010 (Not on truss)Ps = 2 ft. %^i in. X 4 ft. 9!^ in. X 452 = 5,870 R = 5,420 Check 30,260 + p. () = 5,4205,870 -H 4 = 44,700 30,260 The loads are considered concentrated at tlie vertical mem-bers, as shown in Fig. 9. Knowing these forces, the stressesin the members of the side truss are most readily determinedby the graphical method shown in Fig. 10. Starting at thepoint X, the known forces, Pi or xO, p, or On, etc., are laidout. The force R or ml act.« upward and is laid out in tending to P5 and the line la is drawn parallel to tlie bottomchord. The
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Keywords: ., bookcentury1900, bookdecade1910, booksubjectrailroadengineering