A complete and practical solution book for the common school teacher . MENSURA TION 221 PROBLEM parallel sides of a trapezoid are 36 and 24, and the other twosides are each 10: find the width. Solution. (1) Let ABCD represent the trapezoid. (2) DC=24, AB=36, CB=AD=10. (3) AS = EB=(36—24)^-2=6. (4) Now, CEB is a right triangle. (5) EC=VCB2—EBa=8. .*. 8 is the width of the trapezoid. PROBLEM sides, a=6, 6=4, c=5 and d=Sy of a trapeziumcircle, being given, find the area of the trapezium. Solution. (1) Let ABCD be the trapezium. (2) AB = 6, BC=3, CD = 5 and DA =4. (3) Then by Bowse
A complete and practical solution book for the common school teacher . MENSURA TION 221 PROBLEM parallel sides of a trapezoid are 36 and 24, and the other twosides are each 10: find the width. Solution. (1) Let ABCD represent the trapezoid. (2) DC=24, AB=36, CB=AD=10. (3) AS = EB=(36—24)^-2=6. (4) Now, CEB is a right triangle. (5) EC=VCB2—EBa=8. .*. 8 is the width of the trapezoid. PROBLEM sides, a=6, 6=4, c=5 and d=Sy of a trapeziumcircle, being given, find the area of the trapezium. Solution. (1) Let ABCD be the trapezium. (2) AB = 6, BC=3, CD = 5 and DA =4. (3) Then by Bowsers Trigonom- etry, Art. 106, we have S =area and s=\(a-\-b-{-c-{-d). bed in a (4) S = V (s—a) (s—b) (s—c) {s—d) fk;. in PROBLEM 441 What is the edge of the largest cube that can be cut from a hemi-sphere 20 in. in diameter? Solution. (1) Let ALB be the hemi- sphere, and DE the in-scribed cube. (2) ES = ;r, the e6ge of the cube. (3) SP=OP: +*• °r 2 (4) OF = 10 in., ESO is a right triangle. (5) 0?2 = OP2+SP2. (x\* fxy 2x*
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