Lessons in practical electricity; principles, experiments, and arithmetical problems, an elementary text-book . (groups)arranged in parallel (byFormula 39). Prob. 52 : A multiple-series combination of 8cells is joined to an ex-ternal resistance of 3ohms. The cells arearranged 4 in parallel, 2groups in series, Each cell has anE. M. F. of 2 volts andan internal resistance ohm. What currentwill flow through the ex-ternal circuit ? E. M. F. of 1 group = 2 volts. E. M. F. of 2 groups in series = 2 X2 = 4 volts. By Formula (38) Internal resistance of 1 group — — =~± = .125 ohm. E = 2 v
Lessons in practical electricity; principles, experiments, and arithmetical problems, an elementary text-book . (groups)arranged in parallel (byFormula 39). Prob. 52 : A multiple-series combination of 8cells is joined to an ex-ternal resistance of 3ohms. The cells arearranged 4 in parallel, 2groups in series, Each cell has anE. M. F. of 2 volts andan internal resistance ohm. What currentwill flow through the ex-ternal circuit ? E. M. F. of 1 group = 2 volts. E. M. F. of 2 groups in series = 2 X2 = 4 volts. By Formula (38) Internal resistance of 1 group — — =~± = .125 ohm. E = 2 volts, nq = 4 cells in 1 group, r = .5 ohm. By Formula (36) Internal resistance of 2 groups in series = r Xns = .125 X 2 = .25 ohm. r of 1 group = .125 ohm, ns = 2 4 By Formula (31) C = j^q-p = 3 -j- .25 = L23 amPeres- R= 3 ohms, r of 2 groups in series = .25 ohm ; E= 4 volts, 2groups in series. 150. Internal Resistance of any Combination of Cells.— To FIND THE INTERNAL RESISTANCE OF ANY MULTIPLE-SERIES COMBINATION OF CELLS : Multiply the resistance of one cell by the number of cells in one. Fig. 114.—Series-Multiple Grouping of Cells. Four cells in parallel, two groups in series, equivalent to two cells in series and four groups in parallel. 186 PRACTICAL ELECTRICITY. group and divide the product by the number of groups in number of cells in each group must be the r = resistance of one cell; ns = number of cells in series in one group;nq = number of groups in internal resistance of any combination of cells = r_>lILs (40). nq Prob. 53 : Find the internal resistance of a combination of 24 cellsarranged 6 in series, 4 groups in multiple. Each cell has a resistanceof 4 ohms. r X ns 4x6 By Formula (40) Total resistance — = —j— = 6 ohms. r = 4 ohms, ns = 6 cells in one group, nq = 4 groups in multiple. 151. Current Strength from Any Combination of Cells. TO FIND THE CURRENT THAT WILL BE MAINTAINED IN AN EXTERNAL CIRCUIT
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