The essentials of mental measurement . .80 84 88 92 96 100 104 108 Kg. 13. A Type I curve. Urbans Subject II, lighter answers (7) ANALYSIS INTO TWO NORMAL CURVESStage I. Eind the centroid of the frequency curve and calculate /*2» /*3> /*4. /^5. -^4 and -^5- A4 = 9fi2^ - 8/^4, A5 = 30/*2f^ - 3/* 11. Solve the following nonic equation for pj using Sturmsfunctions to localise roots: 24^2 - 28A4P2 + 36/i32p,6 _ (24^03^5 - IOA42) p^ - (I48/X32A4 + 2A52) P2* + (288itx3* - 12AA/^ - A4«) f^+ (24/^2A5 - liL^-K^) fi + 32,^*A4P2 - 24,.36 = 0,and find p^ from ViPi = * Phil. Trans. Soy. Soc. Lond


The essentials of mental measurement . .80 84 88 92 96 100 104 108 Kg. 13. A Type I curve. Urbans Subject II, lighter answers (7) ANALYSIS INTO TWO NORMAL CURVESStage I. Eind the centroid of the frequency curve and calculate /*2» /*3> /*4. /^5. -^4 and -^5- A4 = 9fi2^ - 8/^4, A5 = 30/*2f^ - 3/* 11. Solve the following nonic equation for pj using Sturmsfunctions to localise roots: 24^2 - 28A4P2 + 36/i32p,6 _ (24^03^5 - IOA42) p^ - (I48/X32A4 + 2A52) P2* + (288itx3* - 12AA/^ - A4«) f^+ (24/^2A5 - liL^-K^) fi + 32,^*A4P2 - 24,.36 = 0,and find p^ from ViPi = * Phil. Trans. Soy. Soc. London, 1894. 92 PSYCH0PHYSIC8 [PT. I Stage III. Find y^ and y^ the roots of y2 - ViY + Ti = ^-hy^ and hy^ are the positions of the axes of the normal component curves,where h is the unit of length. Stage IV. The fractions z^ and Zg, that the areas of the componentcurves are of the area of the whole curve, form the roots of the quadratic z^-z~ „P\ = 0. Stage V. The standard deviations are found from CiW = F2 - in^lVz - sPiVi + Pi>. 80 84 88 92 96 100 104 108 112 grams Kg. 14. FBeudo-histogtam analysed into two normal curves, with their Subject I, heavier answers (fit still very poor) The above refers to asymmetrical frequency curves. For symmetricalcurves (where the components have the same axis) modifications arerequired. On carrying out this very troublesome calculation with the hetero-geneous data of Urbans Subject I, heavier answers, the nonic was foundto have three possibly usable roots: but two of these led to imaginaryquantities, leaving only a root which led to the following analysis,approximately: First component Second component Centre 98 grams 101-7 grams <T 5-73 „ 3-54 „ Area 250 200 CH. IV] SKEWNESS AND HETEEOGENEITY 93 The two curvea are drawn on the adjoining figure. On adding themand finding their areas between the appropriate points (84, 88 grams,etc.) we arrive at the following comparison: Urbans Subj ect I, Heavier answers Grams p observe


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