Cyclopedia of locomotive engineering, with examination questions and answers; a practical manual on the construction care and management of modern locomotives . at the outer row of rivets in the unit strip thereis the area of one rivet in single shear to be total resistance, therefore, is 5A x S as follows:.7854x5x45,000=176,715. 3. The plate may tea at the inner row of rivets andshear one rivet in the outer row. The resistance in thiscase would be P - 2D x T x -f A x S as x .4375 x 60,000+ .7854 x 45,000 = 127,218. 4. Failure may occur by crushing in front of thre
Cyclopedia of locomotive engineering, with examination questions and answers; a practical manual on the construction care and management of modern locomotives . at the outer row of rivets in the unit strip thereis the area of one rivet in single shear to be total resistance, therefore, is 5A x S as follows:.7854x5x45,000=176,715. 3. The plate may tea at the inner row of rivets andshear one rivet in the outer row. The resistance in thiscase would be P - 2D x T x -f A x S as x .4375 x 60,000+ .7854 x 45,000 = 127,218. 4. Failure may occur by crushing in front of threerivets. Opposed to this is 3D xTxC, or IX3X•4375 x 95>ooo= 124,687. 5. Failure may occur by crushing in front of tworivets and shearing one. The resistance is representedby 2D x T x C + iA x S; expressed in figures, 1 x 2 x•4375 x 95,000+ .7854 x 45,000 = 118,468. The strength of a solid strip of plate 5^ in. widebefore drilling is P x T x , or x .4375 x 60,000 = 68 LOCOMOTIVE ENGINEERING 144,375, and the efficiency of the joint is 118,125 -s- 144,375 = per triple-riveted butt joint is shown in Fig. 22, the dimensions of. which arefollows: T = T\ in. D = U in. A = .69 in. P = 3^ in. P = 6# in. as Failure mayoccur in thisjoint in eitherone of five 22 I, By tearing the plate at theouter row of rivets, where the pitch is 6^ in. Thenet strength of the unit strip at this point is P-DxT x , found as follows: — .9375 x .4375 x60,000 = 152,578. 2. By shearing four rivets in double shear and onein single shear. In this instance, of the four rivets indouble shear, each one presents two sections, and theone in single shear presents one, thus making a total ofnine sections of rivets to be sheared, and the strengthis 9A x S, or .69 x 9 x 45,000 = 279,450. 3. Rupture of the plate at the middle row of rivetsand shearing one rivet. Opposed to this strain thestrength is P — 2D x T x + iA x S, equivalent - (.9375 x 2) x .4375
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Keywords: ., bookcentury1900, bookdecade1910, booksubjectlocomot, bookyear1916
