. Electric railway journal . ding or descending the sanded track. FIRST PROBLEM When a loaded four-wheel car came to rest at the bot-tom of a sanded track having a 1 per cent grade, it wasnoted that the distance traveled by both axles was 91meters and the running time, 15 seconds. What was thevalue of /? From the previous expression for / we have:2X91 / = ^ X + = X 15The entering speed is 2 x 91 v = - — = meter-seconds = 4^.6 km an Note— is value of g in meters per second per second. It is hardly necessary to add that in the case of trains itis necessar
. Electric railway journal . ding or descending the sanded track. FIRST PROBLEM When a loaded four-wheel car came to rest at the bot-tom of a sanded track having a 1 per cent grade, it wasnoted that the distance traveled by both axles was 91meters and the running time, 15 seconds. What was thevalue of /? From the previous expression for / we have:2X91 / = ^ X + = X 15The entering speed is 2 x 91 v = - — = meter-seconds = 4^.6 km an Note— is value of g in meters per second per second. It is hardly necessary to add that in the case of trains itis necessary to consider the distances traveled by each pairof wheels. It is possible to insert the distance traveled bythe center of gravity of the train when the train is uni-formly loaded. SECOND PROBLEM For incoming trains from Gorlitz the Dresden terminalhas a sanded stub terminal 64 meters long. Assuming thetotal length of a locomotive and tender to be 16 meters andtheir combined weight 75 tons, while the average weight -132-. Half Cross-Section of Sanded Derailing Track at Dresden-Altstadt, Germany distribution of a passenger train is tons per meter,how great is the resistance of the sanded track when / = In the first place, the length of the train is 64 — 16 = 48meters; its weight 48 X 2-5 = 120 tons; the distance cov-ered by the center of gravity of the train — — = 24 2 meters; the distance covered by the center of gravity of the locomotive and tender is 64— — = 56 meters. Therefore, the retarding effort is A = (75 tons X 56 meters + 120tons X 24 meters) = 708 ton-meters. The train massvelocity v to be thus destroyed (adding 6 per cent to thetrain mass for the energy of its rotating masses, or [120tons -f- 75 tons] = tons) is v = y/2><9-8O< = meter-seconds = km an hour. „+... The New Zealand government has made its first movetoward exercising the unlimited powers of regulation oftramways that it recently obtained
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