. Boiler safety orders. crushing strength of plate in front of two rivets =nXdXtXcDivide B, C or D (whichever is the least) by A, and the quotient will be theefficiency of a double-riveted lap joint, as shown in Fig. 22. c =95,000 lb. per sq. in.^=,000 = 49,414£ = (—),000=36,523C =2X44, =38,878D =2 X95,000 =44,531 T£ = 55,000 lb. persq. = & in. = =2% in. = = % in. = = sq. = 44,000 lb. per sq. in. 36,523 (B)49,414 (A) = = efficiency of joint APPENDIX 97 413 Example: Butt and double strap


. Boiler safety orders. crushing strength of plate in front of two rivets =nXdXtXcDivide B, C or D (whichever is the least) by A, and the quotient will be theefficiency of a double-riveted lap joint, as shown in Fig. 22. c =95,000 lb. per sq. in.^=,000 = 49,414£ = (—),000=36,523C =2X44, =38,878D =2 X95,000 =44,531 T£ = 55,000 lb. persq. = & in. = =2% in. = = % in. = = sq. = 44,000 lb. per sq. in. 36,523 (B)49,414 (A) = = efficiency of joint APPENDIX 97 413 Example: Butt and double strap joint, double-riveted. A = strength of solid plate = PXtXTS B = strength of plate between rivet holes in the outer row = (P—d) t X TS C = shearing strength of two rivets in double shear, plus the shearing strength ofone rivet in single shear =NXSXa+nXsXa D— strength of plate between rivet holes in the second row, plus the shearingstrength of one rivet in single shear in the outer row = (P—2d) t X TS+nXsXa. Fig. 23 Example of Butt and Double StrapJoint, Double-Eiveted E = strength of plate between rivet holes in the second row, plus the crushingstrength of butt strap in front of one rivet in the outer row = (P—2d) tXTS+dXbXc F = crushing strength of plate in front of two rivets, plus the crushing strengthof butt strap in front of one rivet =N XdXtXc+nXdXbXc G = crushing strength of plate in front of two rivets, plus the shearing strengthof one rivet in single shear =iVXdX^Xc+nXsXa H= strength of butt straps between rivet holes in the inner row = (P—2d) 2bX TS. This method of failure is not possible for thicknesses of butt strapsrequired by these Rules and the computation need only be made for oldboilers in which thin butt straps have been used. For this reason thismethod of failure will not be considered in other joints. Divide B, C, D, E} F, G-or H (whichever is the least) by A, and the quotient will 98 REPORT OF BOILER CODE COMMITTEE, be the efficienc


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