[Electric engineering.] . 700—Feeders C <c Drop in Feeders 5% 4^of Lamp Vo/tage. Fig. 47.(b) The drop in mains D or E will be 220 X .035 = volts. Thearea of mains D will be A = X 500 X 25 = 35,065 cir. mils. Ans. This would require a No. 5 wire, and a No. 8 or 9 would be sufficientfor the neutral. (c) The area of mains E will be A = X200 X 100 = 56,104 cir. mils, nearly. Ans. A No. 3 B. & S. wire would probably be used for the outside wiresand a No. 6 for the neutral. 16 ELECTRIC LIGHTING. 75 CALCULATIONS FOR ALTERNATING-CURRENT LINES. 82. A load that consists wholly o
[Electric engineering.] . 700—Feeders C <c Drop in Feeders 5% 4^of Lamp Vo/tage. Fig. 47.(b) The drop in mains D or E will be 220 X .035 = volts. Thearea of mains D will be A = X 500 X 25 = 35,065 cir. mils. Ans. This would require a No. 5 wire, and a No. 8 or 9 would be sufficientfor the neutral. (c) The area of mains E will be A = X200 X 100 = 56,104 cir. mils, nearly. Ans. A No. 3 B. & S. wire would probably be used for the outside wiresand a No. 6 for the neutral. 16 ELECTRIC LIGHTING. 75 CALCULATIONS FOR ALTERNATING-CURRENT LINES. 82. A load that consists wholly of lamps possesses verylittle self-induction, and for ordinary lighting systems,where the distances are short, it is usual to make the calcu-lations for lines carrying alternating current in the sameway as already described for the direct-current assumes the power factor to be 1, which is not exactlytrue. If greater accuracy is required, formulas taking intoconsideration the power factor should be used. After theprimary current has been determined and the distance
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