Maryland institute handbook . rivet is required toresist the tensile strain of the platefor a width equal to the center tocenter distance or pitch of therivets. If P equals the strain transmitted from the plate toeach rivet as above, t the thickness of the plate, d thediameter of the rivet, p the pitch of the rivets or centerto center distance between them, St the tensile stress, Sbthe bearing value and Ss the shearing stress, each persquare inch, respectively, for plates and rivets for thenarrow strip represented by the pitch of the rivet;then the resultant stresses produced in single riveted
Maryland institute handbook . rivet is required toresist the tensile strain of the platefor a width equal to the center tocenter distance or pitch of therivets. If P equals the strain transmitted from the plate toeach rivet as above, t the thickness of the plate, d thediameter of the rivet, p the pitch of the rivets or centerto center distance between them, St the tensile stress, Sbthe bearing value and Ss the shearing stress, each persquare inch, respectively, for plates and rivets for thenarrow strip represented by the pitch of the rivet;then the resultant stresses produced in single rivetedjoints would be: Tensile Stress, (St) = strain (P) divided by the dif-ference between the products of the plate thickness (0times the pitch (p) and the thickness (t) times the diame-eter (d). Then the unit tensile stress in the plate,P P 1 tp — td l t{p — d) Bearing, S\> = strain, divided by the thickness timesthe diameter of the rivet; equals the unit compressivestress of the plate and rivet, or s -p Riveted Joints 95. Shearing Stress, S8 = strain, divided by the area ofthe rivet (.7854 d2) or S- P °8 .7854 </2 2nd—Single Shear double riveted joints, in which tworows of rivets, staggered are used. (See Fig. 4) The stresses in double rivetedjoints (single shear) are as follows: Tensile Stress, this is thesame as for single riveted joints. Bearing, S^ = strain, divided bytwice the thickness of the platetimes the diameter of the rivet, or s -p ShearingStress,Ss = 2x78P54x^ 3rd—Butt joints in double shear, in which the edgesof the plates butt one against the other instead of lappingone upon the other (See Fig. 5).A joint of this kind has twocover or splice plates, one ateach side and each of whichlaps over the abutting platesor plates to be joined. Therivets at each side of the jointpass through the two coverplates and through the plate tobe joined, lying between them;that is, they pass through the three thicknesses of will be seen that the rivets ar
Size: 1467px × 1704px
Photo credit: © The Reading Room / Alamy / Afripics
License: Licensed
Model Released: No
Keywords: ., bookcentury1900, bookdecade1920, booksubjectmechanics, bookyear19
