Twentieth century hand-book for steam engineers and electricians, with questions and answers .. . e joint isthe net strip or section of plate, the strength of whichis 59,062 and the efficiency = 59,062 x 100 -*- 85,312 = per cent. A double-riveted butt joint is illustrated by , and the dimensions are as follows: P, inner rowof rivets = 2^in. P, outer rowof rivets = 5^in. Tof plate andbutt straps = T\in. Dof hole anddriven rivet = 1in. Failure may occur in this joint in five distinct ways, which will betaken up in their order. 1. Tearing of the plate at the outer row of net


Twentieth century hand-book for steam engineers and electricians, with questions and answers .. . e joint isthe net strip or section of plate, the strength of whichis 59,062 and the efficiency = 59,062 x 100 -*- 85,312 = per cent. A double-riveted butt joint is illustrated by , and the dimensions are as follows: P, inner rowof rivets = 2^in. P, outer rowof rivets = 5^in. Tof plate andbutt straps = T\in. Dof hole anddriven rivet = 1in. Failure may occur in this joint in five distinct ways, which will betaken up in their order. 1. Tearing of the plate at the outer row of net strength at this point is ,which, expressed in plain figures, results as 1 x .4375 x 60,000= 118,125. 2. Shearing two rivets in double shear and one in .single shear. Should this occur, the two rivets in theinner row would be sheared on both sides of the plate,thus being in double shear. Opposed to this strainthere are four sections of rivets, two for each at the outer row of rivets in the unit strip thereis the area of one rivet in single shear to be added,. FIGURE 98. THE BOILER 307 The total resistance, therefore, is 5A x S as follows:.7854 x 5 x 45,000 = 176,715. 3. The plate may tear at the inner row of rivets andshear one rivet in the outer row. The resistance inthis case would be P — 2D x T x + A x S asfollows: -2 x .4375 x 60,000 + .7854 x 45,000 =127,218. 4. Failure may occur by crushing in front of threerivets. Opposed to this is 3D xTxC, or 1 x 3 x -4375 x95,000= 124,687. 5. Failure may occur by crushing in front of tworivets and shearing one. The resistance is representedby 2D x T x C + iA x S; expressed in figures, Ix2x•4375 x + .7854 x 45,000 = 118,468. The strength of a solid strip of plate 5^ in. widebefore drilling is P x T x , or x .4375 x 60,000 =144,375, and tne efficiency of the joint is 118,125 x 100 ?*?144,375 = per cent. A triple-riveted butt joint is shown in Fig. 99, thedimensions ofwh


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