. Proceedings of the annual convention . (0) Deflection Diagrom for 6| Note: See Appendix for derivotion of equdiions. Assumed Equilibrium ConditionsIMFa+ MieAB ■*■ MieAC + Mioad = 0 M|AB+ M|AC + M|AO=0 Sign of MomentsMoments tending torotote the joint clock-wise ore -t- (b) Conditions for LM = 0 ot Foces of Supports of Joint J* Constant I MiHB = •■ MpAB ■* ^AB ( ~2 6|KA ~ ©iKfl) MiAC = + Kac ( -2eiKA) M|AO - ~ MpAD -^ KaD ^~2Q|KA ~ Q|KD^ 0= IMp^-2lK^(e„J-I(K„e„) Vorioble I MiAB = ■••Mfab + Kab ( -Cab ©ika C 6ikb) MjAC = + Kac (-Cac 6ika) M|AD= -MpAD •*• ^AD ^-CaD 6|KA~ C 9|kd) 0= ZMp^-IK^C^(9
. Proceedings of the annual convention . (0) Deflection Diagrom for 6| Note: See Appendix for derivotion of equdiions. Assumed Equilibrium ConditionsIMFa+ MieAB ■*■ MieAC + Mioad = 0 M|AB+ M|AC + M|AO=0 Sign of MomentsMoments tending torotote the joint clock-wise ore -t- (b) Conditions for LM = 0 ot Foces of Supports of Joint J* Constant I MiHB = •■ MpAB ■* ^AB ( ~2 6|KA ~ ©iKfl) MiAC = + Kac ( -2eiKA) M|AO - ~ MpAD -^ KaD ^~2Q|KA ~ Q|KD^ 0= IMp^-2lK^(e„J-I(K„e„) Vorioble I MiAB = ■••Mfab + Kab ( -Cab ©ika C 6ikb) MjAC = + Kac (-Cac 6ika) M|AD= -MpAD •*• ^AD ^-CaD 6|KA~ C 9|kd) 0= ZMp^-IK^C^(9,KA)-I(KA,Ce,K|) (c) Joint Equotion for I Mja — 0 FIGURE 5 Equivalent Joint Method of Rigid Frame Analysis 19 RIGID FRAME ANALYSIS Frame of Fig. 3 STEP I Conventional Solution Continued No Side Sway Constant I _ ^^FA ^AflQlKB *^A0Q|K0 e Variable I ZMfa KabC0ikb I^aoCOiko •^* 2IKa 2ZKa 2IKaIMfa KKAie,;) 2IKa 2IKa eiA =e,KA-i-2E7AB Relative Value IKaCa ZKaCa ZKaCa _ZMfa Z(KAiCeiKi) Relative Value True Value _ZMfb KKsieiKj) ^KaCa ZKaCaGiA =eiKAv2E|;AB True Value IMfb ,) 2ZKc 2
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