Handbook for architects and builders . = the result: 290 Observing Fig-. 1, it will be seen that aver- 12 age value of Q = I, It will De seen tm1000 J TABIDS n. __ 1000 ihe number of board feet of material in a piece of timber or stud; (f) face by (t) thickness and one ft. in length and the values of same for sizes of material most generally ftused are given in Table II, Col. II. Let — F (5.) Q = F L 10(X) J 12 is com- monly equal either to 1 or IVa, sometimes 1%.Substituting 1 for value of s = studs placed12 from C. (6.) Q= n^^^^)F. V 1000 ^ Size ofstuds lx 11x2 2 X 2 X 2 X 2 X 3 X3 X 3 X 4 X
Handbook for architects and builders . = the result: 290 Observing Fig-. 1, it will be seen that aver- 12 age value of Q = I, It will De seen tm1000 J TABIDS n. __ 1000 ihe number of board feet of material in a piece of timber or stud; (f) face by (t) thickness and one ft. in length and the values of same for sizes of material most generally ftused are given in Table II, Col. II. Let — F (5.) Q = F L 10(X) J 12 is com- monly equal either to 1 or IVa, sometimes 1%.Substituting 1 for value of s = studs placed12 from C. (6.) Q= n^^^^)F. V 1000 ^ Size ofstuds lx 11x2 2 X 2 X 2 X 2 X 3 X3 X 3 X 4 X4 X4 XCOL. 12spacing 16spacing 20spacing i-F Q s= 1h=10 Q 6= 1?-S h=10 .084 .167 .334 .500 .667 . . COL. Ill . COL. IV Q h=-10 .01512, V co/irtECTinG PAETmon. LLU5TRATIVE DETAILOr OKPINARY riGOR AMD PAI^TITION C0n5TRUCTI0in< Fig. 1. Substituting ly^ for value of s = studsspaced 16 from c. (7 ) \pV 1000 / Substituting 1% for value of s = studsspaced 20 from c. (8.) (h^^+J]^)p 1000 To find the average number of Ms ofbd. ft. of framing material contained in asquare of 100 sq. ft. of partition construc-tion take a value of F corresponding to sizeof studs used (see Col. II, Table II below)and a value of L = 10 and substitute ineither formula (5.), (6.), (7.) or (8.). accord-ing to spacing desired. This really will givea partition three or four X f greater in onedimension than 10 ft., but this should beallowed extra for places where the materialwill not cut to advantage. The followingTable II gives the result of such substitu-tion for some of the more commonly usedsizes of joists. (6.) becomes Q = .22 F; (7.)becomes Q = .195 F; (8.) becomes Q = .18 P. Col. I gives sizes of studs or furring strip
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