. Central station heating. loss in heatunits use may be made of the pipe capacity curves heregiven. Multiply the pressure drop given on the curves(Charts Nos. i, 2 and 3) by the factor or constant will give the number of heat units lost per pound ofsteam. This product multiplied by the number of poundsof steam per hour will give the total heat units lost perhour in low pressure steam mains. By referring to Pipe Capacity Curve No. 3. page 29:1000 lbs. steam per hour in a 4-in. pipe 1000 ft. long. Loss =r X X 1000 = 240 Same in a 3-in. pipe = X X looo = 1460
. Central station heating. loss in heatunits use may be made of the pipe capacity curves heregiven. Multiply the pressure drop given on the curves(Charts Nos. i, 2 and 3) by the factor or constant will give the number of heat units lost per pound ofsteam. This product multiplied by the number of poundsof steam per hour will give the total heat units lost perhour in low pressure steam mains. By referring to Pipe Capacity Curve No. 3. page 29:1000 lbs. steam per hour in a 4-in. pipe 1000 ft. long. Loss =r X X 1000 = 240 Same in a 3-in. pipe = X X looo = 1460 Same in a 3y2-in. pipe = X X 1000 = 500 Water Mains.—We have about the same conditionsaffecting the friction in water pipe lines that we have insteam pipes, the velocity, the quantity and the natural laws of gravity also affect the flow. To estimate the loss in in the friction of waterpipes, refer to the pipe curves for water and use the fol-lowing formula: 26 CENTR.\L STATION HEATING. 2 ^ mVE LINE LOSSES 27 00 0 •00 0 1 VI 1 K c>. }^ i: s ^ \ \ \ \, ^ \ V s % \ ^ ^ ^ ^ \ 0 •5 N, \, \, •VJ ^ N \^ \ ji 0 ^ V s. \ k \ s,. \ \ \ 0 ^ s N \ \ V N ;?: N \ N \ ^, „ ^/ \ \ V s \ KT \ \ \ \ H c^ \ \ \ \, N ^ \ N \ ] 5v. \ N \ k ^ \ \ \ C> t.; ^ \ s. \^ sJ - ^ s \ \ \ ~«« X \ V ff v^ N s \, \ ^ ^. ^ ^ ^ \ v V ^ n ^ ^ >v, \ \, IP --1 •v. ^ \l N 7 —, >. N^ s \ a ?~- ?x s J \ \l 0 >>, N «o ^ 1 _J ^Q L .^ K LJ •Q n- y. 0 X i^ s 0 m f: z. S 1 f»^ 0 0. Ik- ^d K Sf-^ 0 - m K- «S k & <0 Qjfi 1 w w 5s § ^?^ 0 Ory Nl z ° a. 2; ^ }J ••j a 3 f 0 p g 0 « n 1 5yV7*^/f )tiy/7^J^V/V*^ MO 7j/ jou 00/i/^i^ 28 CENTR,\L STATION HE.\TING Example:—15,000 sq. ft. radiation, 5-in. pipe 1000 From curve, friction drop is lbs. Loss in = X F X R X = a constant. F = friction drop in lbs. per 100 = radiation shown by = length in 100 ft. In the case cited, loscentralsta
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