. Elements of geometry : containing books I to III. Thus the area of the irregular polygon ABODE is equalto the sum of the areas of the triangles ABE, EBD, DBC. II. Tin polygon may be co verted into a single triaoj i qua! <• It ABODE be a pentagon, we can convert it into anequivalent quadrilateral by the following pro. Join l,l> and draw CF parallel to BD, mooting ED pro-duced in /•. and join BF. Then will quadrilateral ABFE» pentagon ABODE. For . BDF .!:, on Bame base BD and betweensum- parallels. If, then, from the pentagon we remove a BCD, and add BDF to the remainder, we obtain a qua
. Elements of geometry : containing books I to III. Thus the area of the irregular polygon ABODE is equalto the sum of the areas of the triangles ABE, EBD, DBC. II. Tin polygon may be co verted into a single triaoj i qua! <• It ABODE be a pentagon, we can convert it into anequivalent quadrilateral by the following pro. Join l,l> and draw CF parallel to BD, mooting ED pro-duced in /•. and join BF. Then will quadrilateral ABFE» pentagon ABODE. For . BDF .!:, on Bame base BD and betweensum- parallels. If, then, from the pentagon we remove a BCD, and add BDF to the remainder, we obtain a quadrilateral ABFEeq livalent to the pentagon ABODE. Books I. & II.] AREA OF AX IRREGULAR POLYGON, ior The quadrilateral may then, by a similar process, be con-verted into an equivalent triangle, and thus a polygon of anynumber of sides may be gradually converted into an equiva-lent triangle. The area of this may then be found. III. The third method is chiefly employed in practice bySurveyors
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