. American engineer and railroad journal . Front E Right ISM« FiB. 5Effect o£ weight ot eccentric roil boss and % eccentric rod at 45 x 5%14; = ■ = 18 lbs. nearly C„ 1485% x 18 lbs. rr 24 lbs 62 4- — 18 4- C, = O Cj t= 5% lbs. c= 6 lbs 10 Combining all horizontal and \ rrtical forces 1—2—3—4—5—6—7—8—9—10 separtely, we have— Horizontal — 911 + 131 + 59 + 219 + 24 = 1,346 lbs. Vertical 1,295 — 93 + 46—1,716 + 6 = 462 lbs. Hence the counterbalance weight will be placed at an anglewhose tan. = 462 -j- 1,346, which is 18° 57 (or 19°)+ 90° = 109°back of the right-hand wri-l pin. Its magni
. American engineer and railroad journal . Front E Right ISM« FiB. 5Effect o£ weight ot eccentric roil boss and % eccentric rod at 45 x 5%14; = ■ = 18 lbs. nearly C„ 1485% x 18 lbs. rr 24 lbs 62 4- — 18 4- C, = O Cj t= 5% lbs. c= 6 lbs 10 Combining all horizontal and \ rrtical forces 1—2—3—4—5—6—7—8—9—10 separtely, we have— Horizontal — 911 + 131 + 59 + 219 + 24 = 1,346 lbs. Vertical 1,295 — 93 + 46—1,716 + 6 = 462 lbs. Hence the counterbalance weight will be placed at an anglewhose tan. = 462 -j- 1,346, which is 18° 57 (or 19°)+ 90° = 109°back of the right-hand wri-l pin. Its magnitude will be theresultant of these two forces. - 766 — 2,142 4-766 4-Ci C, Upward Forces. 873 x 28 = J 21= 11,697,712 x 16 = 11,392 47,533 62 = 766 lbs. •873•557•712 = 0 lbs. 933 lbs i a 766 sin. 7 1,076 sin. 7° = 131 lbs H The vertical components oE these i .nv only considcu-tl, _J TJe resultant = R = | +462= = 1,423 lbs. (at 14 ra-dius). The counterbalance
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Keywords: ., bookcentury1800, bookdecade1890, booksubjectrailroadengineering
