. The Decorator's assistant. 2) 549 = area required. PROBLEM XV, To find the area of the segment of a circle. Find the area of the sector a d c b a, or thatof A D c E F A, by the preceding problem, ac-cording as the area of the less or greater seg-ment is required. Find the area of the triangle a c d, formedby the chord a c of the segments, and the radiiD a, D c, of the sectors. Then, the sum or difference of these areas,according as the segment is greater or lessthan a semicircle, will be the Example 1.—What will be the area of theless segment a c b a, the radius d a being 20inc
. The Decorator's assistant. 2) 549 = area required. PROBLEM XV, To find the area of the segment of a circle. Find the area of the sector a d c b a, or thatof A D c E F A, by the preceding problem, ac-cording as the area of the less or greater seg-ment is required. Find the area of the triangle a c d, formedby the chord a c of the segments, and the radiiD a, D c, of the sectors. Then, the sum or difference of these areas,according as the segment is greater or lessthan a semicircle, will be the Example 1.—What will be the area of theless segment a c b a, the radius d a being 20inches, the chord a c inches, the lengthof the arc a b c inches, and the perpen-dicular D G inches ? 2) sq. in. = area of the sector a b c d a. 1345211210134522242 2) sq. in. = area of triangle a d c. sq. in. = area required. Example 2.—What will be the area of thegreater segment a c e f a, the length of thearc A F E c being inches, the radius d a,the chord a c, and the perpendicular d g, tobe of the same dimensions as those given inthe preceding example ? 2) sq. in. = area of sector a d c e f. 2) sq. in. = area of triangle a d c, sq. in. = area required (To be continued.) THE decorators ASSISTANT. 191 23riclt0* On reference to tlie sacred records, we findthat the use of brick has arisen in very prime-val times; the city of Ba
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