. Algebraic geometry; a new treatise on analytical conic sections . PK IS Fio. 76. ^ = rcos{6 - 26^). [ r cos(e - a)] 122. To find the polar equation of a circle which passes throughthe origin and has its centre at the point (a, a). Let P(r, 6) be any pt. P(K0J. Pig. 77. .. r = 2a cos (^ - a), as before. on the circle, 0 itscentre, and draw CKperpendicular to OP. ^0PC = ; = 6l-o; .. 0P=20K = 200 cos (5-a); .. r = 2aCOS(6-a)is the required equation. Alternative OB is the diameterthrough O, OP = OBcosPOB; 116 POLAR EQUATION OF A CIRCLE. [chap. vii.

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