Engineering and Contracting . m one cross sectionto another as units, multiplying the volumeof each such prism in the overhaul masses ofexcavation and embankment by the distance infeet between its center of mass and theproper adjoining limit of free haul. Add theexcavation items and embankment items intwo separate amounts. The sum of thesetwo amounts divided by the volume in theoverhaul mass of excavation will be the over-haul distance in feet. The volume (in cubicyards) in the overhaul mass of excavationmultiplied by the overhaul distance in , gives the number of units of over-
Engineering and Contracting . m one cross sectionto another as units, multiplying the volumeof each such prism in the overhaul masses ofexcavation and embankment by the distance infeet between its center of mass and theproper adjoining limit of free haul. Add theexcavation items and embankment items intwo separate amounts. The sum of thesetwo amounts divided by the volume in theoverhaul mass of excavation will be the over-haul distance in feet. The volume (in cubicyards) in the overhaul mass of excavationmultiplied by the overhaul distance in , gives the number of units of over-haul. While Method II is applicable to approxi-mate estimates. Method III should be usedin preparing final estimates to do justice tocontractors as well as railway companies. At the top of Fig. 1 is shown a short sec-tion of profile, the number of cubic yardsof excavation or embankment in each 100-ft. station being indicated thereon. In themass diagram below the profile the graphicaldetermination of the distance (640 ft.) be-. lOOOCu YdsMoss inclusive Free Haul Mass3000 - - tobemoved 6000 ?? Profile and Mass Diagram Used in Comparison of Methods of Computing Overhaul. treat with the overhaul masses only, comput-ing the overhaul by subtracting the free haulfrom the distance between the centers of theoverhaul masses. The number of units ofoverhaul are computed by multiplying thelength of overhaul in 100-ft. stations by thenumber of cubic yards in the overhaul unfairness of this method in final es-timates to contractors is illustrated in by the dotted profile and dotted section ofthe mass diagram, which shows a case wherethe total overhaul mass (5,200 cu. yds.) andthe center of overhaul mass remain the sameas in the example used for comparison ofmethods, but the haul distance becomes effect on the overhaul distance and numberof units of overhaul as computed by MethodIII for this increase in length of haul isgiven in the comparison under
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