. Design of an exhaust gas calorimeter for automobile engines . fft/A/ *2 Fc/l,l. Load. -45* In using the rational equationspreviously mentioned the voume of mixturewas found by multiplying the piston displace-ment by the number of explosions and thetemperature of the exhaust. The heat lost inthe exhaust per hour is found by multiplyingthe weight of the exhaust gases per hour, bythe specific heat, and by the temperaturechange. This can be expressed by the follow-ing formulae: hr. = WSQtT-ffi1) 1 W = weightAof mixture pep fer. B£ = no. of cu. ft. of S- Specific hea
. Design of an exhaust gas calorimeter for automobile engines . fft/A/ *2 Fc/l,l. Load. -45* In using the rational equationspreviously mentioned the voume of mixturewas found by multiplying the piston displace-ment by the number of explosions and thetemperature of the exhaust. The heat lost inthe exhaust per hour is found by multiplyingthe weight of the exhaust gases per hour, bythe specific heat, and by the temperaturechange. This can be expressed by the follow-ing formulae: hr. = WSQtT-ffi1) 1 W = weightAof mixture pep fer. B£ = no. of cu. ft. of S- Specific heat of mixtureT = temp, of Exhaust gasesffi*= temp of room. i . 5 - - , Load. /^W »/. /££?/? Hg /3 /pis/v. **£. F~ci_l. Load Ca&* LBS. CALCULATED HEAT IN EXHAUST GAS Toatal displ = vol piston diapl x EPMx 60 = x x 4 = 1805 cu ft per hour. Gas per hour = from log. Air per hour = Total rlispl - gas per hour = 1805 - = Air / hr. lbs= Air /hr cu ft = = lbs Gas / = gas per hr. cu. ft x .084 = x = Total lbs = piUs = BTD in EXH = lbs. exh gas x diff tempxSpec H = (900~60) x = 25,700 % lost in Exh= = t 158000 . . - ? - . ? . SAMPLE CALCULATIONS = GAS ABS TEMP x ST. PR. ~.TEMF x PR. AT METER x 580 x 50 x 12 = x Cu ft / hr x heat value gas = BTU supplied/hr. x 705 = 158,000. BTU supplied / hr. x 2546 = heat equiv of IHP. x 2546 = heat equiv of IHPl Heat equiv = $ heat in supplied = % heat in ,000 Diff. in temp, x water / hr. =
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