. Tentative revised boiler safety orders. e second row in single shear and one rivet insingle shear in the outer row = (P—) t X TS-\-nXsXa P--strength of plate between rivet holes in the second row, plus the crushingstrength of butt strap in front of one rivet in the outer row = (P—2d) tXTS-]-dXbXc 102 ESPORT OF BOILER CODE COMMITTEE, G = strength of plate between rivet holes in the third row, plus the crushing strength of butt strap in front of two rivets in the second row and one rivet in the outer rov/ = (P—4d) tXTS+nXdXbXcff=crushing strength of plate in front of eight rivet
. Tentative revised boiler safety orders. e second row in single shear and one rivet insingle shear in the outer row = (P—) t X TS-\-nXsXa P--strength of plate between rivet holes in the second row, plus the crushingstrength of butt strap in front of one rivet in the outer row = (P—2d) tXTS-]-dXbXc 102 ESPORT OF BOILER CODE COMMITTEE, G = strength of plate between rivet holes in the third row, plus the crushing strength of butt strap in front of two rivets in the second row and one rivet in the outer rov/ = (P—4d) tXTS+nXdXbXcff=crushing strength of plate in front of eight rivets, plus the crushing strength of butt strap in front of three vwets—NXdXtXc-{-nXdXbXc/=crushing strength of plate in front of eight rivets, plus the shearing strength of two rivets in the second row and one rivet in the outer row, in single shear=NXdXtXc+nXsXaDivide B, C, D, E, F, G, H ov I (whichever is the least) by Af and the quotientwill be the efficiency of a butt and double strap joint quadruple-riveted, as shownin Fig. Fig. 29 Example of Butt and Double Strap Joint, Quadeuple-Eiveted T>S=55,0001b. persq. in. i= 3^ in. = in. h= a^ in. = = H in. = in. a= sq. ,000 lb. per sq. ,0001b. persq. ,000 lb. per sq. in. Number of rivets in single shear in a unit length of joint =3. Number of rivets in double shear in a unit length of joint = = 15 X55,000 = 412, = (15—) ,000 = 386,718C=8 X88,000 X +3 X44,000 = 577,000I) = (15—) ,000+1X44,,310i7 = (15—) ,000+3X44,,494F = (15—2 ) X55,000+ X95,000 = 399,902(? = (15—) ,000+,000 = 426,269£? =,000+,000 = 473,145/=,000+3X44, =447,369 386,718 jB)412,500 {A) = = efficiency of joint APPENDIX 103 416 Figs. 30 and 31 illustrate other joints that may
Size: 2219px × 1126px
Photo credit: © The Reading Room / Alamy / Afripics
License: Licensed
Model Released: No
Keywords: ., bookcentury1900, bookdecade1910, booksubjectsteambo, bookyear1919
