Heat engineering; a text book of applied thermodynamics for engineers and students in technical schools . nksas shown in Fig. 114. The actual position could be found byusing the connecting rods or if infinite rods are assumed the pro-jections may be used. Thus if the compression is to occur stroke on the high-pressure cylinder, the diagram for an in-finite connecting rod would be shown in Fig. 114, with a crank MULTIPLE EXPANSION ENGINES 245 of From this it is seen that the low-pressure piston willhave moved of its stroke when compression occurs in thehigh-pressure cylinder. The
Heat engineering; a text book of applied thermodynamics for engineers and students in technical schools . nksas shown in Fig. 114. The actual position could be found byusing the connecting rods or if infinite rods are assumed the pro-jections may be used. Thus if the compression is to occur stroke on the high-pressure cylinder, the diagram for an in-finite connecting rod would be shown in Fig. 114, with a crank MULTIPLE EXPANSION ENGINES 245 of From this it is seen that the low-pressure piston willhave moved of its stroke when compression occurs in thehigh-pressure cylinder. The high-pressure piston is at the middleof the stroke when the low-pressure stroke begins. Suppose that the cylinders have a ratio of 1 to 4 and theclearance is 6 per cent, on the high and 5 per cent, on the that the receiver volume is times the volume of thehigh-pressure cylinder; that the cut-off occurs at stroke inhigh-pressure cylinder and stroke in low; that compressionis at stroke from end on high and on low and that piis 150 lbs. gauge and pb is 2 lbs. Fig. 114.—Diagram by which to find piston position. (Finite or infinite connecting rod.) Call the volume swept out by the high-pressure cylinder 1 andusing Fig. 113: Vh = 1 Vi = + = Vi = 4 V2 = + = = V3 Vr = 74 = + = = Vb Vch = X 1 = 76 = + = Vcl = X 4 = V7 = = V8 V 9 = = = X 4 + = = X 4 + = = 4 + = = V13Vu = 4 X + = p2 = X ™| = X +pn X Q . K . A ,QV> = + = 345 + °-43^11 ( +^) _0 . P4 = + = 472 + °59?>11 ( +) + -QO,nK1>lPo = P9 = 1 36 + 02 = + Pn 246 HEAT ENGINEERING Plb = 2 X 02 = 10 ( + ) . P6 = Pl° = + + = UA + °-41 Pl1( + ( + ) Pii = + — = 22A + °-264 ^n 22.
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