On the Diffraction of Light Incident at Nearly the Critical Angle on the Boundary between Two Media . 6. Critical Angle on the Boundary between Two Media. 511 aperture, and if we assume this amplitude to be proportional to the cosine ofthe angle of diffraction 0, we obtain finally I = I0 sin2 (f>/(f)2 = Ii cos2 6 sin2 <£/<£2, where Ii is sensibly a constant within the diffraction-pattern. On this basis,,the ratio of the intensity of corresponding bands on either side of the patternshould be cos2#i/cos2#2 where 6\ and 02 are the respective angles of diffraction,and this, as we have see


On the Diffraction of Light Incident at Nearly the Critical Angle on the Boundary between Two Media . 6. Critical Angle on the Boundary between Two Media. 511 aperture, and if we assume this amplitude to be proportional to the cosine ofthe angle of diffraction 0, we obtain finally I = I0 sin2 (f>/(f)2 = Ii cos2 6 sin2 <£/<£2, where Ii is sensibly a constant within the diffraction-pattern. On this basis,,the ratio of the intensity of corresponding bands on either side of the patternshould be cos2#i/cos2#2 where 6\ and 02 are the respective angles of diffraction,and this, as we have seen agrees with the results of the photometric deter-mination (Section 3, above). The foregoing also enables us to calculate the displacement of the positionof maximum intensity in the pattern from that given by Snells law. Wemay obtain the position of maximum intensity from the expression for Ias given above, by putting dl/d0 equal to zero. It is found that for thisposition, the phase-angle is not zero, but is approximately given by , X 3 sin 6 9 =— • Th-ird cosJ0 The angles of diffra


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