. Canadian Shipping and Marine Engineering January-December 1918. his difference and add half from 10 to10 and half from 2 to 2=. Connect 1 to2 to locate the outline for the bottom ofthe side sheet. To obtain the curved line 9 to 10, itis necessary to find out the points W Tand Y. This is done in the followingmanner: Divide C D, Fig. 2, into fourequal parts, and through these pointsdraw the planes WW XX and YYparallel to the line A B. Project thepoints X and X through, and at rightangles to A B, thus locating the pointsX and X on X X\ which is shown on,and is continued on each side of A and B.
. Canadian Shipping and Marine Engineering January-December 1918. his difference and add half from 10 to10 and half from 2 to 2=. Connect 1 to2 to locate the outline for the bottom ofthe side sheet. To obtain the curved line 9 to 10, itis necessary to find out the points W Tand Y. This is done in the followingmanner: Divide C D, Fig. 2, into fourequal parts, and through these pointsdraw the planes WW XX and YYparallel to the line A B. Project thepoints X and X through, and at rightangles to A B, thus locating the pointsX and X on X X\ which is shown on,and is continued on each side of A and the line F R M intersects the lineX X, locate the point 15. Also locate 16where K S N intersects the line X is already located on X X. Projectthese points 15 and 16, and T down toand at right angles to X^ X* Continuethese projections as shown in the half section view through X X. On the eleva-tion. Fig. 2, raise the perpendicular 15,15° to its intersection of its arc F R° this perpendicular length andtransfer to the line 15, 15° in the half-. FIG. 4. TEMPLET FOR THROAT SHEET. sectional view X X, Fig. 2. At rightangles to K S N draw the perpendicuiar16, 16° intersecting the semicircle K S°N at 16°. Transfer this length 16, 16^to 16 16° in the sectional view for thisplane, which is X X. T T° is drawn atright angles to C T D, and its lengthtransferred to T T° in the sectional view. The distance X X° in the sectionalview is equal to the distance through Xon the line X X in the elevation. Thisdistance is not shown in the elevationview, but it is obtained by using a littlejudgment. The distance through thepo>.it 5 13 equal to 5 5° and through thepoint 3 is equal to 3 3°, so if X was mid-way between the points 3 and 5, it wouldbe equal to the mean of the two distances3 3° and 5 5°. But X is nearer to 5 than3, so it will be seen that it is not difficultto get the distance X X° for the cross-section. An even curve drawn throughthe points T° 16° 15°
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Keywords: ., bookcentury1900, bookdecade1910, bookidc, booksubjectshipbuilding
