. Electric trains . 212 2-0 0-5 12 19-229-043-0 49-0 69-3 14598-0 19-729-844-4 50-571-5101-1 155 20-230-545-5 52-073-5104-0 163 20-631-146-3 53-275-3104-0 172 20-931-747-4 54-477-0108-9 180 21-232-248-2 55-578-6111-1 187 21-532-748-9 56-680-0113-2 194 21-833-249-6 57-581-3115-0 200 22-033-650-4 58-482-6116-8 206 22334-050-9 69-283-8118-0 212 22-534-461-5 60-084-8120-0 218 To/ace p. 56.] ENERGY CONSUMPTION 57 The train consumption, making the 9 per cent, allowance forrotational momentum, is equal to— (0-0303 X r2) w hr per ton(218 X C X M) w hr per ton or = (218 I w hr per ton-mile M = (218 X C
. Electric trains . 212 2-0 0-5 12 19-229-043-0 49-0 69-3 14598-0 19-729-844-4 50-571-5101-1 155 20-230-545-5 52-073-5104-0 163 20-631-146-3 53-275-3104-0 172 20-931-747-4 54-477-0108-9 180 21-232-248-2 55-578-6111-1 187 21-532-748-9 56-680-0113-2 194 21-833-249-6 57-581-3115-0 200 22-033-650-4 58-482-6116-8 206 22334-050-9 69-283-8118-0 212 22-534-461-5 60-084-8120-0 218 To/ace p. 56.] ENERGY CONSUMPTION 57 The train consumption, making the 9 per cent, allowance forrotational momentum, is equal to— (0-0303 X r2) w hr per ton(218 X C X M) w hr per ton or = (218 I w hr per ton-mile M = (218 X C) w hr per ton-mile. This result shows that the limiting train consumption per ton-mile for any given values of acceleration and deceleration is, underthe assumed conditions, the same for any length of run. Q, theduration of stops, may usually be taken as 20 seconds. The highestattainable schedule speeds, and the corresponding crest values, havebeen calculated, by means of the above formulae, for runs of 0*5, 1, 2. SO /CO y30 /so 200 T/me /h <3econc/s 290300 Fig. 31.—Speed-time Diagram for 1-mile Run covered at Schedule Speeds of 12, 18,and 24 ml ph, with Constant Acceleration and Braking, and neglecting Train-friction. and 4 miles, and for various rates of acceleration and results are embodied in Table XIX. (folding table). As an instructive instance of the application of these principles,let us consider the case of a 1-mile run from start to stop, letus consider a case where M = IO. Let us first study this run forschedule speeds of 12, 18, and 24 ml ph. The speed-time diagramscorresponding to these three schedule speeds, for A = IO and B = 1*5,are readily worked out from the formulae and methods alreadydescribed, and are plotted in Fig. 31. 58 ELECTRIC TRAINS Assuming 100 per cent, efficiency for the electrical equipment andnegligible train-friction, the input required will be exclusively thatcorresponding in each case to the momentum at the crest
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