. Theory and calculation of alternating current phenomena . power, P, and canceling,we get, p _ E^ VAO^ .o^ ^10 . ^ - V ^^,,j^ - ^^n ^,^ or KE^ ^ V 10^-« _ 710=^ , ^ ~ > wUere A — ?? ^^.^^^^ — ^?^ ^ V or, substituting 77 = , we have A = |-^j-g; or, substituting V = Al, where / = length of magnetic circuit. ^^^^ ^,,^ -----^^ and 58r,E-H10 _ 191AE-H ^~~ /O-e^^ — ^0,6^ In Figs. 85, 86, and 87 is shown a curve of hysteretic loss,with the loss of power as ordinates, andin curve 85, with the
. Theory and calculation of alternating current phenomena . power, P, and canceling,we get, p _ E^ VAO^ .o^ ^10 . ^ - V ^^,,j^ - ^^n ^,^ or KE^ ^ V 10^-« _ 710=^ , ^ ~ > wUere A — ?? ^^.^^^^ — ^?^ ^ V or, substituting 77 = , we have A = |-^j-g; or, substituting V = Al, where / = length of magnetic circuit. ^^^^ ^,,^ -----^^ and 58r,E-H10 _ 191AE-H ^~~ /O-e^^ — ^0,6^ In Figs. 85, 86, and 87 is shown a curve of hysteretic loss,with the loss of power as ordinates, andin curve 85, with the , E, as abscissas, for ^ = 6, A = 20, / = 100, and n = 100; in curve 86, with the number of turns as abscissas, for I = 6, A - 20, / = 100, and E = 100; EFFECTIVE RESISTANCE AND REACTANCE 125 Rl LATION BETWt EN Eand P F OR 1 = 5,A =20,/ = = 10 = 1 00 / A / / o n / / i / / v / 4 y ^ /- ^ ^ ^ [T E.^ 20 40 GO 60 100 130 HO 100 180 200 220 210 2G0 230 300 320 310 300 380 400 120 410 Fig. 85.—Hysteresis loss as function of RELATION BETWEEN n AND PFOR i = ,/= = 100. 150 200 250 300 n = NUMBER OF TURNS Fig. 86. 350 400 126 AL TERN A TING-C URREN T PHENOMENA in curve 87, with the frequency, /, or the cross-section, A, as abscissas, for I = Q, n ^ 100, and E = 100. As shown, the hysteretic loss is proportional to the * power of the , inversely proportional to the *^ power of the number of turns, and inversely proportional to the * powerof the frequency and of the cross-section. 90858075 RELATION BETWEEN N AND PFOR A = 20, ; = 6,m = 65 60 55 |50 0 45 II 40 35 30 25 \ \ 1 V \ 20 \ 15 10 V, --. — . b 100 200 300 / = FREQUENCY Fig. 87. 400 99. If <7 = effective conductance, the power component of acurrent is / = Eg, and the power consumed in a conductance, g,is P = IE = E^g. Since, however, ^ ^ P = ^^luT we have K -^^^ ^ ^^Jit is: , = „^ = 58 0 = 191 4 J y ^).6^^ ^^^^ ^^,^^1.
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Keywords: ., bookcentury1900, bookdecade1910, booksubjectelectriccurrentsalte
