. Journal of electricity, power, and gas . will be seen that while the wheel travels fromJ to K the bucket is discharging the full 4-in. stream,and similar lines drawn through the lower F and upperU will show a shorter arc, located further along in thedirection of motion, for the full 6-in. stream discharge. The length (S) of the slug of water taken care ofby each bucket depends upon the pitch (B) of thebuckets measured on the pitch circle, and the pitch line May 21, 1910) JOURNAL OF ELECTRICITY, POWER AND GAS 475 velocity (<^) relative to the spouting velocity, and isgiven bv the formula:
. Journal of electricity, power, and gas . will be seen that while the wheel travels fromJ to K the bucket is discharging the full 4-in. stream,and similar lines drawn through the lower F and upperU will show a shorter arc, located further along in thedirection of motion, for the full 6-in. stream discharge. The length (S) of the slug of water taken care ofby each bucket depends upon the pitch (B) of thebuckets measured on the pitch circle, and the pitch line May 21, 1910) JOURNAL OF ELECTRICITY, POWER AND GAS 475 velocity (<^) relative to the spouting velocity, and isgiven bv the formula: This will be the same in all parts of the stream,although the ends of the slugs will not be square. As the operation of receiving and discharging iscontinuous, with no piling up of the water in thebuckets, the time of discharge will be equal to the timeof receipt, and the question becomes one of velocitiesand areas. The area of the jet and its velocity aregiven and it remains to determine those quantities inconnection with the Fig. 2. Fig. 2 is a section through two buckets on thepitch line, and shows the diagram used to determinedischarge velocities. Let A = Area of jet in square = Pitch line spacing of = Space occupied by bucket = Space between buckets available for = Thickness of buckets at = Radial length of discharge. V ^ Spouting velocity of water. V =^ Axial component of discharge = .Angle of discharge. = Ratio of pitch line velocity to spouting velocity,o = Ratio of discharge velocity to spouting = Ratio of axial component of discharge to spouting velocity. Then c = sm. PD = B —C (9= (V —(^) sin. p. The product of the area of the jet by its velocityequals the product of the area of discharge by the axialcomponent of its velocity. As there are two dischargesthe formula is AV = 2 V DL and A V substituting the ratios, 41, 5 51, 6 61, 10°, the results are
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Keywords: ., bookcentury1800, bookdecade1890, bookidjo, booksubjectelectricity
