. Journal of electricity, power, and gas . -. ab is 8% of the receiver pressure; that is, the PRloss in line is 8% at full non-inductive load. ac represents, then, in magnitude and direction,the pressure consumed over the line by the powercomponent of the receiver current. If for a laggingcurrent we make the angle cag = 0 (5 is the angle bywhich the receiver current lags behind the receiverpressure), and the angle acg = 90°, then cy = I sine VW+Jjjwy, as can be proved by simple geometry. That is, eg represents inmagnitude and direction the pressure consumed over the line bythe wattless compone


. Journal of electricity, power, and gas . -. ab is 8% of the receiver pressure; that is, the PRloss in line is 8% at full non-inductive load. ac represents, then, in magnitude and direction,the pressure consumed over the line by the powercomponent of the receiver current. If for a laggingcurrent we make the angle cag = 0 (5 is the angle bywhich the receiver current lags behind the receiverpressure), and the angle acg = 90°, then cy = I sine VW+Jjjwy, as can be proved by simple geometry. That is, eg represents inmagnitude and direction the pressure consumed over the line bythe wattless component of the receiver current. (If the receiver. VALUES OF EoFig. 2. Regulation of Transmission System. and the same power-factor, the regulation is 17%. as shown bythe point h. Jt is seen that for any given case it is only necessary to Febiuary 5, 1910] JOURNAL OF ELECTRICITY, POWER AND GAS. 121 determine the triangle abc; the remainder of the figure is drawnmechanically. The labor of making the drawing for each casemay be eliminated if, instead of laying off oa to represent a par-ticular receiver pressure, we let it represent any receiver pressureand call this pressure 100%, Fig. 3ii. ^arcsntage Pressure Above Feceiver


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