. Graphical and mechanical computation. ^ N ■^ x\ \ n\ V X ^ v\\ ^ fN ^■■-s \ w ■^ ^ \^ \ ^ ■^ ~4 \ \ ^ , --3 V — ~Z 1 .3 4 5 6 78910 m. 3 4- S 6 7 B3I0(U) Fig. I6a. Fig. i6b. Fig. I 6c. Fig. 16a illustrates this representation. Given values of 11 and v, sayUk and Vk, we find the point {uk, Vk) as the point of intersection of the cor-responding vertical and horizontal lines, and read Wk from the curve pass-ing through this point. If the point (jik, Vk) falls between two of thecurves Wj and wu we interpolate by sight the required value of Wk betweenWj and ivi. Again, given values of 11 and w, s

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. Graphical and mechanical computation. ^ N ■^ x\ \ n\ V X ^ v\\ ^ fN ^■■-s \ w ■^ ^ \^ \ ^ ■^ ~4 \ \ ^ , --3 V — ~Z 1 .3 4 5 6 78910 m. 3 4- S 6 7 B3I0(U) Fig. I6a. Fig. i6b. Fig. I 6c. Fig. 16a illustrates this representation. Given values of 11 and v, sayUk and Vk, we find the point {uk, Vk) as the point of intersection of the cor-responding vertical and horizontal lines, and read Wk from the curve pass-ing through this point. If the point (jik, Vk) falls between two of thecurves Wj and wu we interpolate by sight the required value of Wk betweenWj and ivi. Again, given values of 11 and w, say Uk and Wk, we find the pointof intersection of the vertical Hk and the curve Wk, and read Vk from thehorizontal passing through this point. Thus, in Fig. i6a, 11 =3, v =4give w = 3; u = t„v = give w = ; z^ = 4, w = 5 give v = As in Art. 11, we may avoid drawing the horizontals and verticals,and use a transparent sheet containing two perpendicular index lines,/„ and /„ (Fig. 166); thus, if « = 3 and v = 6, slide the sheet keeping theindex lines parallel to the axes until /„ passes through u = 2> and /„

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