. Perspective for art students . BCD. AC and BD, as wellas others, vanish there at the The extension ofAC to K gives AK equal in fact to AI, but here shownsmaller, because the line KAC is subject to the influenceof vanishing. KP will also be in the vertical plane. Itis shown continuing by a dotted line downwards, and willstrike the vertical line through some inches What is true of this plane in which ABCD lies istrue of planes parallel to it. Thus EG- and FH bothvanish to the same point as AC and BD, that is, to Similarly, LQ will vanish to the same point as KP. A t


. Perspective for art students . BCD. AC and BD, as wellas others, vanish there at the The extension ofAC to K gives AK equal in fact to AI, but here shownsmaller, because the line KAC is subject to the influenceof vanishing. KP will also be in the vertical plane. Itis shown continuing by a dotted line downwards, and willstrike the vertical line through some inches What is true of this plane in which ABCD lies istrue of planes parallel to it. Thus EG- and FH bothvanish to the same point as AC and BD, that is, to Similarly, LQ will vanish to the same point as KP. A third plane is represented by the line MUG. Wehave, of course, horizontal planes in the figure, the baseFBHD and the top containing all the points E, L, E, G,N, K, A, M, I, J, 0, and C. Of these N is the centre ofthe square EAGC, and by means of it we push out thediagonals to get M and 0. If we join M to P and 0 toS, we gain the mitre lines where the two sloping surfacesLKQP and UPS intersect. ?» « ti % * s sacis Jo gNii r#VA. ? oN do aais ttO argil DMiHriNV/^ 04 46 Perspective What kinds of planes are these sloping surfaces in?LKQP is in a directly descending. It is directly descend-ing because its trace LK is parallel to the picture, andthe perpendicular to this trace KP is running directlyaway just as KA is. If the lines KP and LQ were con-tinued till they met somewhere below , the point ofconvergence would be a point in the farther edge of thesloping plane. The farther edge (or vanishing line)would be parallel to the nearer edge LK. The angularline MP is also in this directly descending plane, andits would be on the vanishing line just de-scribed. SO, the other angular line, must not be confused asgoing to the same vanishing point as MP. The plane inwhich SO occurs is similar in its relation to the object tothe plane of MP, but instead of descending the plane ofSO ascends. S is nearer to us than 0, while M is nearerthan P. MP in No. 2 would, however, go to the sam


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