Electrical measurementsA laboratory manual . = ; R = C = mf., the deflection was + 65 scale parts. (7 = — 15 To balance, C = Therefore, L = X X = condenser was a microfarad subdivided into .5, .2, .2, .05,.05 mf. I SELF-IXDUCTION AND MUTUAL INDUCTION. 253 119. Rimingtons Modification of MaxwellsMethod/ — In this method one side of the condenseris connected to F (Fig. 118), and the other side to apoint jV, whichcan be shiftedalong so as tovary r withontany change inthe resistance Rof that this arrange-ment the dis


Electrical measurementsA laboratory manual . = ; R = C = mf., the deflection was + 65 scale parts. (7 = — 15 To balance, C = Therefore, L = X X = condenser was a microfarad subdivided into .5, .2, .2, .05,.05 mf. I SELF-IXDUCTION AND MUTUAL INDUCTION. 253 119. Rimingtons Modification of MaxwellsMethod/ — In this method one side of the condenseris connected to F (Fig. 118), and the other side to apoint jV, whichcan be shiftedalong so as tovary r withontany change inthe resistance Rof that this arrange-ment the dis-charges through the galvanometer, due to the discharge of the condenserand the self-induction of the coil, are in opposite direc-tions and equal, when both balances have been y be the current flowing in the arms Q and S^ whenit has reached its steady value, and x that in P and R. Let both keys be closed and then let Ki be quantity of electricity which passes through thegalvanometer, due to self-induction in ^, is. Ly R+ S _ Lya Q + a(R + S} a + R + S F+Q+G-a a + R^-s This is the integral of the current between the limits0 and y. The quantity passing through the galva-nometer from the discharge of the condenser is Cxr F+Q Cxr-h p_u ^-u ^(-P + ^) 0- + P+Q R + s+ah Phil. Mag., Vol. XXIV., 1887, p. 54. 254 BLECTBICAL MEASUliEMENTS. This discharge passes while the current through r fallsfrom X to zero. These quantities pass through the galvanometer inopposite directions, and if there is no deflection, Lya _ Cxr-b But and F+ Q+ aa B + S+ ab Lya ^Ly (^R+ S)^ F -^ Q+ G-a e Oxrb Oxr (P + Q^ B + s+ab~ c Hence Ly (R + S} = Cxr (P + 0. Now5 = 4. Therefore i .:^= |. ^,= |,y P y R+ S P R-\-S R since PS— QR. Hence L= Cr-^.R If r = P, we have Maxwells formula,L= OQR. The resistance must be such that r can be adjustedwithout changing the value of P after a balance hasbeen obtained for steady currents. The double com-mutator, illustrated in Fig. 47, may be used in t


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