. Electric railway journal . £, = (X+Xi+X^)^ cos (A + B + C) H^ = (X + Jfi+^j)tan(A + B + 0 Ti = H + Hi + H2 + H:, Then use same solution for Spiral H0+ P) = 90° - iD Tan l(P-O) = (ft,+ fi) + (ft3 + £i)P = HR + 0) + HP-0)0 = HP + 0) - HP-0) (R, + ^1) sin Dsin P tan i{P + 0) Given radii and angles of any compound tangents and external. Draw be, cd, ef and gl parallel to T, de, fg and ghparallel to R, gj parallel to 7, and gk parallel to mo bc = (R — Ri) sin A, cd = (R^ — R,) sin (A + B), ef= (ft, — ft,) sin (A +B + C)ob = (ft — ft,) cos A, de = (ft, — ft,) cos (A + B),fg = (ft,—
. Electric railway journal . £, = (X+Xi+X^)^ cos (A + B + C) H^ = (X + Jfi+^j)tan(A + B + 0 Ti = H + Hi + H2 + H:, Then use same solution for Spiral H0+ P) = 90° - iD Tan l(P-O) = (ft,+ fi) + (ft3 + £i)P = HR + 0) + HP-0)0 = HP + 0) - HP-0) (R, + ^1) sin Dsin P tan i{P + 0) Given radii and angles of any compound tangents and external. Draw be, cd, ef and gl parallel to T, de, fg and ghparallel to R, gj parallel to 7, and gk parallel to mo bc = (R — Ri) sin A, cd = (R^ — R,) sin (A + B), ef= (ft, — ft,) sin (A +B + C)ob = (ft — ft,) cos A, de = (ft, — ft,) cos (A + B),fg = (ft,— ft,) cos (A+B + C)gh= R — (ab + de + fg),ih = bd + efjh = gh tan (90° — A)Similarily from Spiral No. 2 find gk and klT = gl + ih—jhT = jg + km — kl. Given ft,, ftexternal ft, tan ^ E = 2T- (ft. ft,) sin e . Asin-2 Ri (2) E = yw gh + Tm — ft. AT = 90° + angle of Spiral No. 2M=90° + A + B + Cd sin (iV - ft) Ht =H sin Adsin (M - 0) ft,+ E=T (ft,+ £,)* +ff\- 2(ft,+ i,,)//4CosM*T = 1\ + H,T = 7, + Hr,E = (ft, + E) - ft. If Spiral No. 1 is the same as Spiral!No. 2 Then D H, = sin - (ft, + B,),(A + B + C + f) ft, + B = cos(A + g + C)(ft,+ giy(a + B + C + I) cosAnd ffi =,//5 *Note that this is a continu-ption of th oxprpssion underthe radical sign above.
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Keywords: ., bookcentury1900, bookdecade1900, bookpublishernewyorkmcgrawhillp
