Van Nostrand's eclectic engineering magazine . (42.) The intensity of this horizontal load maybe expressed thus _ dH __ J (Vcoti) (4S.) dy ay ay At B the vertical load = Yi- Let thisbe represented by B K (Fig. 29). If thecord be itself vertical at that point, B K =Yi will be equal to the pull along it at the cord is inclined as in the figure, drawits tangent at B, and B L = B K cosec i|=: Vj cosec i^= pull alongthe cord. and K L = B K cot 1*1 =V| cot ii = horizontal com-ponent of this pull. Ho — Vi cotij ==Hi = resultant of entire hori-zontal load on A B. It may often happen that S E = Y
Van Nostrand's eclectic engineering magazine . (42.) The intensity of this horizontal load maybe expressed thus _ dH __ J (Vcoti) (4S.) dy ay ay At B the vertical load = Yi- Let thisbe represented by B K (Fig. 29). If thecord be itself vertical at that point, B K =Yi will be equal to the pull along it at the cord is inclined as in the figure, drawits tangent at B, and B L = B K cosec i|=: Vj cosec i^= pull alongthe cord. and K L = B K cot 1*1 =V| cot ii = horizontal com-ponent of this pull. Ho — Vi cotij ==Hi = resultant of entire hori-zontal load on A B. It may often happen that S E = Y cot ^= horizontal component of the pull alongthe cord at D (Fig. 30) is greater than G S= F N = Ho = horizontal pull along thecord at A. In such cases G E = H^ - Y THEORY OF ARCHES. 291 cot ^ is negative, which indicates that thehorizontal load between A and D, for atleast a part of this distance, must be con-trary in direction to that heretofore dis-cussed ; that it must exert an inward pullinstead of an outward one (Fig. 30). If Tia. this inward pull were removed or re-placed by an outward one, the curve wouldevidently be flattened about A. We may illustrate geometrically, the re-lation between the forces in all parts ofAB. The vertical load and curve being givendraw F E^ (Fig. 32) = the total vertical
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