. Stresses in railway structures on curves . can be easily found from Ordin. = §(b + £e + 2qh) or Ordin. = ^ (b - 2e), according to whether they are for the outer or for the inner girder. (1) Maximum Moments. Panel points B and F Z = , e = , b = , qh = Outer Girder: Ord. = 7-5R ( - 2 x .9513 +2 x ) = Inner Girder: Ord. 19*25 d9-25 + 2 x .9513) = Panel points C and E Z = 15 e = Outer Girder: Ord. = xg1^ ( - 2 x .5980 + 2 x ) - Trine?* Girder* Ord = —ll__(i9425 + 2 x .5980) - Panel point D 2 = 22 5 e = Ou
. Stresses in railway structures on curves . can be easily found from Ordin. = §(b + £e + 2qh) or Ordin. = ^ (b - 2e), according to whether they are for the outer or for the inner girder. (1) Maximum Moments. Panel points B and F Z = , e = , b = , qh = Outer Girder: Ord. = 7-5R ( - 2 x .9513 +2 x ) = Inner Girder: Ord. 19*25 d9-25 + 2 x .9513) = Panel points C and E Z = 15 e = Outer Girder: Ord. = xg1^ ( - 2 x .5980 + 2 x ) - Trine?* Girder* Ord = —ll__(i9425 + 2 x .5980) - Panel point D 2 = 22 5 e = Outer Girder: Ord. = -g it! ( - 2 x .4802 + 2 x ) =19. cu Inner Girder: Ord. 22. 5 = 19>25 ( + 2 x .4802) = The influence lines are shown in Fig. 22 The area of influence lines for the outer girder ( (b)) ie Ax » 15 (2 x + 2 x + ) = 15 x 71. 9684 = and that for the inner girder (Fig. 22 (c)) is A2 = 15 (2 x + 2 x + ) = 15 x 71. 9689 = Fig. 22. If we use an equivalent uniform load of 5295 lbs. per footof girder, then each girder will have a bending moment of x3295 = 3,557,000 The direct stress in the bottom flanges of the girders is945,000/ - 49,000 lbs., being in tension for the outer and incompression for the inner girder. 64 (2) Maximum Shears. The influence ordinates for shears are computed as follows 56 ?anel point B 2 = ■£ e = 6x1 a. 25 5 6x19 . 25 - 2 2 3x19. 25 2 ( - 2 x .9513+ 2 x .8613 Panel point C Z = | e - Outer Girder: Ord. c r7_^ -—( - 2 x .5980 + 2 x ) = .7133 Inner Girder: Ord. = g & 19 2&( + 2 x .5980) = .7081 Panel point D 2 = \ e = tL_ 2 Outer Girder: Ord. ^j^ 19 •25 - 2 x .4802 + 2 x ) - .5413 Inner Girder: Ord. = gxi^ 25(19-25 + 2 x -4802) r .5249Panel point E Z 3 e = -5980 Outer Girder: Ord. = —-±—-( - 2 x .5980 + 2 x ) = .3567 Inner Girder: O
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