. Electric railway journal . hoe pressure, or 449,260 lb. Thetotal friction generated by the brakeshoes is 35 per centof the total actual shoe pressure, or 157,241 lb. This isthe total equivalent weight of the train multiplied ; therefore the rate of retardation of the train willbe times the acceleration of gravity, or = The total shoe friction of one motor car is 35 per centof the total actual shoe pressure of one motor and onetrailer truck, or 17,738 lb., while the total force requiredto retard the car is ,250, or 17,669 lb. Thisleave
. Electric railway journal . hoe pressure, or 449,260 lb. Thetotal friction generated by the brakeshoes is 35 per centof the total actual shoe pressure, or 157,241 lb. This isthe total equivalent weight of the train multiplied ; therefore the rate of retardation of the train willbe times the acceleration of gravity, or = The total shoe friction of one motor car is 35 per centof the total actual shoe pressure of one motor and onetrailer truck, or 17,738 lb., while the total force requiredto retard the car is ,250, or 17,669 lb. Thisleaves a balance of 69 lb., required to act through the draw-bar in retaining trail cars. Likewise the total shoe friction of a trail car is 11,025 lb.,as compared with 11,186 lb., required to retard the leaves 161 lb. by which the motor cars must retardeach trail car through drawbar pull. In so far as the transfer of weight is concerned, it isimmaterial whether the drawbar reaction consists of a single 21,149/b. . FORCES ACTING UPON MOTOR TRUCK OF MOTOR CAR, MOTOR TRUCK LEADING force at one end of a car, or is the algebraic sum of forcesacting at both ends of the ear, since the drawbars are allassumed to be at the same height from the rail. In analyz-ing the transfer of loads we shall therefore consider thedrawbar reaction to be a push of 69 lb., forcing the body ofthe motor car forward, and to be a pull of 161 lb., forcingthe body of the trail car back. Referring to the diagram showing forces acting on thebody of a motor car, let us consider first the motor truckas leading. The first force to consider is that due to theinertia of the car body, which acts horizontally forward through the center of gravity and is equal to timesthe weight of the body, or 8099 lb. This force acts 35^ the center plate. Next in importance are the motor and trailer-truck pull-rod forces which act horizontally, forward 4 in. above andrearward 1 in. below the center plates
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