. Railroad construction. Theory and practice . the same as Eq. 112, but Fig. 149. r+ig=(R-i9) sin (ff sm((p-Fy (116). Fig. 150. Problem. To find the dimensions of a connecting curve run-ning to the INSIDE of a curved main track; number 9 frog, 4° 30curve, d = 13, 5r = 48i^ 286 RAILROAD CONSTRUCTION. §274. Solution. Eq. 112. rf=13 000 log 2n= g= 4 708 log id-g)= .91866 (d-g)= 8 292 co-log (2jB-rf) = 22 = log tan ^* = 27? = i4 = 3°22 14 272-d = * = 6° 44 28 log(2i2-rf) = F = 6° 21 35(*-F) = 0°2253 Eq. 116. 22 = /og(/2-i^) = ig=

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. Railroad construction. Theory and practice . the same as Eq. 112, but Fig. 149. r+ig=(R-i9) sin (ff sm((p-Fy (116). Fig. 150. Problem. To find the dimensions of a connecting curve run-ning to the INSIDE of a curved main track; number 9 frog, 4° 30curve, d = 13, 5r = 48i^ 286 RAILROAD CONSTRUCTION. §274. Solution. Eq. 112. rf=13 000 log 2n= g= 4 708 log id-g)= .91866 (d-g)= 8 292 co-log (2jB-rf) = 22 = log tan ^* = 27? = i4 = 3°22 14 272-d = * = 6° 44 28 log(2i2-rf) = F = 6° 21 35(*-F) = 0°2253 Eq. 116. 22 = /og(/2-i^) = ig= log sin * = (R-ig) = co-log sin (i - F) - 2. 17676 (^_ir) = 1373, log = (r + ^ff) = . r = log sin (*-i^) = d = 0° 15 Eq. 114. ^(*-F) = .. (r-*7) = sin i(*-F)... BinK*-i^) = F.^ = 274. Crossover between two parallel straight tracks. (See Fig- 151.) The turnoutsare as usual. The cross-over track may be straight,as shown by the full lines,or it may be a reversedc

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