. Design of a direct current generator and switchboard for a farm power plant. ound tobe 2 volts. Therefore the voltage generated at full loadmust be 110 + 5+ + 2 * practically 118 volts. From this value of voltage the flux that is neededto generate it was found from the equation m E x 10* 118 x IP6 _ 1,250,000 = z n 472 x 20 This is the flux for the teeth and air gap. The flux for thearmature body is x 1,250,000 = 625,000 lines. Applyingthe leakage coefficient, , the flux for the pole core is1,2 x 1,250,000 * 1,500,000 lines and that for the yoke is i^ooo = 750j000 lin
. Design of a direct current generator and switchboard for a farm power plant. ound tobe 2 volts. Therefore the voltage generated at full loadmust be 110 + 5+ + 2 * practically 118 volts. From this value of voltage the flux that is neededto generate it was found from the equation m E x 10* 118 x IP6 _ 1,250,000 = z n 472 x 20 This is the flux for the teeth and air gap. The flux for thearmature body is x 1,250,000 = 625,000 lines. Applyingthe leakage coefficient, , the flux for the pole core is1,2 x 1,250,000 * 1,500,000 lines and that for the yoke is i^ooo = 750j000 lines> The densities for each part of the magnetic circuitwere then found by dividing the flux for that part by thearea of the path through that part. Then referring to theiron curves as was done for the no load conditions, the am-pere turns per unit length were found for the respectivedensities and, when multiplied by the length of the paththrough each part, gave the total ampere turns for that the ampere turns for the separate parts gave the totalampere Part ArmatureTeethAir GapPole CoreYoke Density Ampere Turns Total Unit for eachLength 76,00075,50053,20094,40028,850 part32103125190180
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Keywords: ., bookcentury1900, bookdecade1910, booksubjecttheses, bookyear1912
