. Railroad construction. Theory and practice. A textbook for the use of students in colleges and technical schools . Fig. 31. 50 EAILROAD CONSTRUCTION. §48. 48. To find the deflections from any point of the = 730. Tan hQV=by-^Q¥; tan cQV^^cc^Qc; we are enabled to find the deflection angles from the tan-gent at Q to any point of the spiral. The tangent to the curve at c (Fig. 32) makes slk angle ofV. Fig. °30 with QV, or cmV = 1°S0\ Qcm=cmV-cQm, Thevalue of cQm is known from previous work. The deflectionfrom c to Q then becomes known. acm = cmV—cap = cmV—caq—qap. caq is
. Railroad construction. Theory and practice. A textbook for the use of students in colleges and technical schools . Fig. 31. 50 EAILROAD CONSTRUCTION. §48. 48. To find the deflections from any point of the = 730. Tan hQV=by-^Q¥; tan cQV^^cc^Qc; we are enabled to find the deflection angles from the tan-gent at Q to any point of the spiral. The tangent to the curve at c (Fig. 32) makes slk angle ofV. Fig. °30 with QV, or cmV = 1°S0\ Qcm=cmV-cQm, Thevalue of cQm is known from previous work. The deflectionfrom c to Q then becomes known. acm = cmV—cap = cmV—caq—qap. caq is the deflection an-gle to c from the tangent at a and will have been previouslycomputed numerically, gap = 15. acm therefore becomesknown. 6cm = i of 45=2230;dcn = iof 60=30. §49. ALIGNMENT. 51 ecn=ec6!—ncd, ncd^^=^cmV, tan ecd = {ee—6!^d^-^ce\ allof which are known from the previous work. By this method the deflections from the tangent at any point
Size: 1225px × 2041px
Photo credit: © Reading Room 2020 / Alamy / Afripics
License: Licensed
Model Released: No
Keywords: ., bookcentury1900, bookdecade1910, bookpublishernewyo, bookyear1913